分享鏈接使用whatsapp

Question

我用這些代碼共享應用程序鏈接什麼是應用程序，但沒有什麼是在WhatsApp的文本字段。如果使用簡單文本，那麼它的工作。任何人都可以提出最終結果。

NSString *theTempMessage = @"whatsapp://send?text=https://itunes.apple.com/in/app/myapp/id1054375332?ls=1&mt=8"; 
NSString *theFinalMessage; 

theTempMessage = [theTempMessage stringByReplacingOccurrencesOfString:@":" withString:@"%3A"]; 
theTempMessage = [theTempMessage stringByReplacingOccurrencesOfString:@"/" withString:@"%2F"]; 
theTempMessage = [theTempMessage stringByReplacingOccurrencesOfString:@"?" withString:@"%3F"]; 
theTempMessage = [theTempMessage stringByReplacingOccurrencesOfString:@"," withString:@"%2C"]; 
theTempMessage = [theTempMessage stringByReplacingOccurrencesOfString:@"=" withString:@"%3D"]; 
theFinalMessage = [theTempMessage stringByReplacingOccurrencesOfString:@"&" withString:@"%26"]; 

NSString * stringToSend=theFinalMessage; 
NSURL *whatsappURL = [NSURL URLWithString:stringToSend]; 

if ([[UIApplication sharedApplication] canOpenURL: whatsappURL]) 

{ 
    [[UIApplication sharedApplication] openURL: whatsappURL]; 
} 

Answer 1

跟隨誤差顯示白名單您的應用希望在Info.plist中查詢LSApplicationQueriesSchemes鍵（字符串數組）下的任何URL方案：

隨着方案包括在Info.plist的一切和以前一樣。當你連接到iOS 9時，你不僅限於50個不同的方案，你只需要在Info.plist中聲明你需要的東西。對於您可以包含多少計劃似乎沒有限制，但如果他們認爲您濫用此機制，我會希望App Store審覈團隊提出問題。

Note that this mechanism only applies to canOpenURL and not openURL. You do not need to have a scheme listed in Info.plist to be able to open it with openURL.

NSString * msg = @"Application%20Name%20https://itunes.apple.com/in/app/myapp/id1054375332?ls=1&mt=8"; 

msg = [msg stringByReplacingOccurrencesOfString:@":" withString:@"%3A"]; 
msg = [msg stringByReplacingOccurrencesOfString:@"/" withString:@"%2F"]; 
msg = [msg stringByReplacingOccurrencesOfString:@"?" withString:@"%3F"]; 
msg = [msg stringByReplacingOccurrencesOfString:@"," withString:@"%2C"]; 
msg = [msg stringByReplacingOccurrencesOfString:@"=" withString:@"%3D"]; 
msg = [msg stringByReplacingOccurrencesOfString:@"&" withString:@"%26"]; 

NSString * urlWhats = [NSString stringWithFormat:@"whatsapp://send?text=%@",msg]; 
NSURL * whatsappURL = [NSURL URLWithString:urlWhats]; 

if ([[UIApplication sharedApplication] canOpenURL: whatsappURL]) { 
    [[UIApplication sharedApplication] openURL: whatsappURL]; 
} else { 
    UIAlertView * alert = [[UIAlertView alloc] initWithTitle:@"WhatsApp not installed." message:@"Your device has no WhatsApp installed." delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil]; 
    [alert show]; 
} 

This是應用安全的WWDC 2015年官方視頻。

Answer 2

如果使用 「[[UIApplication的sharedApplication]的OpenURL：whatsappURL];」 後弦replcement它會打開Safari瀏覽器沒有的WhatsApp，

如果你想打開的WhatsApp不檢查canOpenURL

failed for URL: "whatsapp://" - error: This app is not allowed to query for scheme whatsapp

當在iOS中9，你必須替換字符串

Answer 3

添加到您的Info.plist

<key>LSApplicationQueriesSchemes</key> 
    <array> 
     <string>whatsapp</string> 
    </array> 

，你需要打開WhatsApp的共享實現此代碼到ViewController。 （例如像說一個按鈕動作） 更新迅速版本3（Xcode的8.x中）：更新了棄用：

var str = "This is the string which you want to share to WhatsApp" 
str=str.addingPercentEncoding(withAllowedCharacters: (NSCharacterSet.urlQueryAllowed))! 
let whatsappURL = URL(string: "whatsapp://send?text=\(str)") 
if UIApplication.shared.canOpenURL(whatsappURL) { 
    UIApplication.shared.open(whatsappURL!, options: [:], completionHandler: nil) 
} else { 
    showAlert(message: "Whatsapp is not installed on this device. Please install Whatsapp and try again.") 
} 

這裏showAlert（）是用於顯示警報的自定義功能。