6
我有一個來自我的數據庫的項目表和我想要刪除按鈕的每個項目。每個字段的刪除按鈕
目前它正在工作,但按鈕顯示ID號,我想它只是說「刪除」。
我還是希望它的基礎上刪除了joke.ID
$result = mysqli_query($con, "SELECT joke.id, joketext, jokedate, name, email FROM joke INNER JOIN author ON authorid = author.id");
echo "<form action='delete1.php' method='post'>
<table border='1'>
<tr>
<th>Joke</th>
<th>Date</th>
<th>Name</th>
<th>Email</th>
<th>Delete</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
echo "<tr>";
echo "<td>" . $row['joketext'] . "</td>";
echo "<td>" . $row['jokedate'] . "</td>";
echo "<td>" . $row['name'] . "</td>";
echo "<td>" . $row['email'] . "</td>";
echo "<td><input type='submit' name='deleteItem' value='".$row['id']."' /></td>";
echo "</tr>";
}
echo "</table>";
echo "</form></br>";
mysqli_close($con);
?>
這是delete1.php
if (isset($_POST['deleteItem']) and is_numeric($_POST['deleteItem'])) {
// here comes your delete query: use $_POST['deleteItem'] as your id
mysqli_query($con,"DELETE FROM joke WHERE id='$_POST[deleteItem]'");
}
mysqli_close($con);
header('Location: joke1.php');
exit();
?>
我只想按鈕,說 「刪除」
的HTML在你的* EDIT1 *是真正可怕的。只需將表單,隱藏輸入和提交按鈕全部放在最後一個表格單元中 – Phil
做到了。謝謝。 – kushpf
你剛剛錯過了EDIT1中的一點語法,除了那個工程很棒,謝謝 –