在斯卡拉開始我的第一步,我遇到了第一個誤解。
我拿了一個鏈表的典型例子。斯卡拉鍊接列表
sealed trait List[+A] // `List` data type, parameterized on a type, `A`
case object Nil extends List[Nothing] // A `List` data constructor representing the empty list
/* Another data constructor, representing nonempty lists. Note that `tail` is another `List[A]`,
which may be `Nil` or another `Cons`.
*/
case class Cons[+A](head: A, tail: List[A]) extends List[A]
object List { // `List` companion object. Contains functions for creating and working with lists.
def sum(ints: List[Int]): Int = ints match { // A function that uses pattern matching to add up a list of integers
case Nil => 0 // The sum of the empty list is 0.
case Cons(x,xs) => x + sum(xs) // The sum of a list starting with `x` is `x` plus the sum of the rest of the list.
}
def product(ds: List[Double]): Double = ds match {
case Nil => 1.0
case Cons(0.0, _) => 0.0
case Cons(x,xs) => x * product(xs)
}
def apply[A](as: A*): List[A] = // Variadic function syntax
if (as.isEmpty) Nil
else Cons(as.head, apply(as.tail: _*))
val x = List(1,2,3,4,5) match {
case Cons(x, Cons(2, Cons(4, _))) => x
case Nil => 42
case Cons(x, Cons(y, Cons(3, Cons(4, _)))) => x + y
case Cons(h, t) => h + sum(t)
case _ => 101
}
}
有幾個問題:
1)爲什麼自定義鏈表類並不衝突內置scala.collection.immutable.List.type
2)爲什麼一段代碼被認爲當我們是正確的將內置List與自定義鏈表進行匹配?
val x = List(1,2,3,4,5) match {
case Cons(x, Cons(2, Cons(4, _))) => x
case Nil => 42
case Cons(x, Cons(y, Cons(3, Cons(4, _)))) => x + y
case Cons(h, t) => h + sum(t)
case _ => 101
}
感謝您的回覆。但是如何使用建築清單(1,2,3,4,5)呢?應用方法有這樣的機會嗎? –
您正在調用'List'對象的'apply [A](as:A *):List [A]'方法。 –