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我面對我的服務有問題,一個數據集將填補,並轉換成一個序列化的XML對象:轉換的XDocument到了IEnumerable <詞典<字符串,對象>>
string xmlString;
System.Xml.Serialization.XmlSerializer oSerializer = new System.Xml.Serialization.XmlSerializer(typeof(DataSet));
DataSet ds = new DataSet();
StringBuilder sb = new StringBuilder();
using (StringWriter sw = new StringWriter(sb))
{
oSerializer.Serialize(sw, ds);
xmlString = sb.ToString();
}
此代碼返回我一個DataSet :
<?xml version="1.0" encoding="utf-16"?>
<DataSet>
<xs:schema id="NewDataSet" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
<xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:Locale="">
<xs:complexType>
<xs:choice minOccurs="0" maxOccurs="unbounded">
<xs:element name="Table">
<xs:complexType>
<xs:sequence>
<xs:element name="ID" type="xs:int" minOccurs="0" />
<xs:element name="CheckboxCol" type="xs:int" minOccurs="0" />
<xs:element name="Last_x0020_Name" type="xs:string" minOccurs="0" />
<xs:element name="First_x0020_Name" type="xs:string" minOccurs="0" />
<xs:element name="User_x0020_Group" type="xs:string" minOccurs="0" />
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:choice>
</xs:complexType>
</xs:element>
</xs:schema>
<diffgr:diffgram xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1">
<NewDataSet>
<Table diffgr:id="Table1" msdata:rowOrder="0">
<ID>1</ID>
<CheckboxCol>0</CheckboxCol>
<Last_x0020_Name>patel</Last_x0020_Name>
<First_x0020_Name>krunal</First_x0020_Name>
</Table>
<Table diffgr:id="Table2" msdata:rowOrder="1">
<ID>46</ID>
<CheckboxCol>0</CheckboxCol>
<Last_x0020_Name>123</Last_x0020_Name>
<First_x0020_Name>123</First_x0020_Name>
<User_x0020_Group>123</User_x0020_Group>
</Table>
<Table diffgr:id="Table3" msdata:rowOrder="2">
<ID>47</ID>
<CheckboxCol>0</CheckboxCol>
<Last_x0020_Name>def</Last_x0020_Name>
<First_x0020_Name>abc</First_x0020_Name>
<User_x0020_Group />
</Table>
</NewDataSet>
</diffgr:diffgram>
</DataSet>
現在我不知道如何閱讀或轉化爲List<Dictionary<string, object>>
,或者我可以綁定到一個Silverlight Datagrid的任何其他對象。
我認爲這個問題已經足夠具體,英語已經足夠好了。我已經看到更糟的,但設法得到的重點。 – AnthonyWJones
好的...抱歉。我不習慣在這裏回答問題。以爲我今天就試試:) –
我收到錯誤 'List> list = myDoc.Root.Elements()。Where(e => e.Name.LocalName ==選擇(col => new Dictionary (){** new ** KeyValuePair ()** {** col.Name,col.Value}})。ToList ();' 方法'Add'沒有超載需要1個參數\t 無法使用集合初始化程序初始化類型'System.Collections.Generic.KeyValuePair ',因爲它沒有實現'System.Collections.IEnumerable ' –
Chirag