2016-07-16 125 views
2

你好,我試圖讓Django的自定義用戶模型,但我得到以下錯誤。 -Django自定義登錄模型錯誤

ERRORS:

auth.User.groups:(fields.E304)關於 'User.groups' 衝突與關於 'Freelancer.groups' 反向存取反向存取。 提示:爲'User.groups'或'Freelancer.groups'的定義添加或更改related_name參數。 auth.User.user_permissions: (fields.E304)'User.user_permissions'的反向訪問者爲'Freelancer.user_permissions'與反向訪問者衝突 。 提示:爲'User.user_permissions'或'Freelancer.user_permissions'的定義添加或更改related_name參數。 login.Freelancer.groups:(fields.E304)反向訪問者 'Freelancer.groups'與'User.groups'的反向訪問者衝突。 提示:爲'Freelancer.groups'或'User.groups'的定義添加或更改related_name參數。 login.Freelancer.groups: (fields.E331)字段通過模型 'login.Freelancer_groups'指定了一個多對多關係,該關係尚未安裝。 login.Freelancer.user_permissions:(fields.E304)反向訪問者 'Freelancer.user_permissions'與反向訪問者衝突 'User.user_permissions'。 提示:爲'Freelancer.user_permissions'或'User.user_permissions'的定義添加或更改related_name參數。 login.Freelancer.user_permissions:(fields.E331)字段通過 'login.Freelancer_user_permissions'指定 多對多關係,該關係尚未安裝。

系統檢查發現6個問題(0沉默)。

models.py:

from django.contrib.auth.tests.custom_user import CustomUserManager 
from django.db import models 
from django.utils import timezone 
from django.utils.http import urlquote 
from django.utils.translation import ugettext_lazy as _ 
from django.contrib.auth.models import AbstractBaseUser, BaseUserManager, PermissionsMixin 
from crm import settings 


class FreelancerManager(BaseUserManager): 
    def create_user(self, name, skills, password=None): 
     if not name: 
      raise ValueError('Users must have a unique name ') 

     user = self.model(
      name=self.name, 
      skills=skills, 
     ) 
     user.set_password(password) 
     user.save(using=self._db) 
     return user 

    def create_superuser(self, name, skills, password): 
     """ 
     Creates and saves a superuser with the given email, date of 
     birth and password. 
     """ 
     user = self.create_user(
      name, 
      password=password, 
      skills=skills, 
     ) 
     user.is_admin = True 
     user.save(using=self._db) 
     return user 


class Freelancer(AbstractBaseUser, PermissionsMixin): 
    name = models.OneToOneField(settings.AUTH_USER_MODEL, 
           related_name='Freelancer_profile', 
           verbose_name='name', 
           max_length=20, 
           unique=True,) 

    field_of_interest = models.CharField(max_length=200) 
    skills = models.TextField() 
    experience = models.TextField() 

    is_active = models.BooleanField(default=True) 
    is_admin = models.BooleanField(default=False) 

    objects = FreelancerManager() 

    USERNAME_FIELD = 'name' 
    REQUIRED_FIELDS = ['skills'] 

    class Meta: 
     db_table = 'auth_user' 
     verbose_name = _('user') 
     verbose_name_plural = _('users') 

    def get_absolute_url(self): 
     return "https://stackoverflow.com/users/%s/" % urlquote(self.name) 

    def get_short_name(self): 
     return self.name 

    def get_full_name(self): 
     return self.name 

    def __str__(self): # __unicode__ on Python 2 
     return self.name 

    def has_perm(self, perm, obj=None): 
     # "Does the user have a specific permission?" 
     # # Simplest possible answer: Yes, always 
     return True 

    def has_module_perms(self, applabel): 
     # "Does the user have permissions to view the app `app_label`?" 
     # Simplest possible answer: Yes, always 
     return True 

    @property 
    def is_staff(self): 
     # "Is the user a member of staff?" 
     # "Simplest possible answer: All admins are staf" 
     return self.is_admin 

# class Clients(models.Model): 
#  name = models.CharField(max_length=20) 
#  firm_name = models.CharField(max_length=20) 
#  reference = models.CharField(max_length=200) 
#  chu = models.CharField(max_length=200) 
# 
#  def __str__(self): 
#   return self.name 

admin.py:

# from django.contrib import admin 
# from login.models import Freelancer 
from django import forms 
from django.contrib import admin 
from django.contrib.auth.models import Group 
from django.contrib.auth.admin import UserAdmin as BaseUserAdmin 
from django.contrib.auth.forms import ReadOnlyPasswordHashField 
from .models import Freelancer 


class UserCreationForm(forms.ModelForm): 
    """A form for creating new users. Includes all the required 
    fields, plus a repeated password.""" 
    password1 = forms.CharField(label='Password', widget=forms.PasswordInput) 
    password2 = forms.CharField(label='Password confirmation', widget=forms.PasswordInput) 

    class Meta: 
     model = Freelancer 
     fields = ('name', 'skills') 

    def clean_password2(self): 
     # Check that the two password entries match 
     password1 = self.cleaned_data.get("password1") 
     password2 = self.cleaned_data.get("password2") 
     if password1 and password2 and password1 != password2: 
      raise forms.ValidationError("Passwords don't match") 
     return password2 

    def save(self, commit=True): 
     # Save the provided password in hashed format 
     user = super(UserCreationForm, self).save(commit=False) 
     user.set_password(self.cleaned_data["password1"]) 
     if commit: 
      user.save() 
     return user 


class UserChangeForm(forms.ModelForm): 
    """A form for updating users. Includes all the fields on 
    the user, but replaces the password field with admin's 
    password hash display field. 
    """ 
    password = ReadOnlyPasswordHashField() 

    class Meta: 
     model = Freelancer 
     fields = ('name', 'password', 'skills','is_admin') 

    def clean_password(self): 
     # Regardless of what the user provides, return the initial value. 
     # This is done here, rather than on the field, because the 
     # field does not have access to the initial value 
     return self.initial["password"] 


class FreelancerAdmin(BaseUserAdmin): 
    # The forms to add and change user instances 
    form = UserChangeForm 
    add_form = UserCreationForm 

    # The fields to be used in displaying the User model. 
    # These override the definitions on the base UserAdmin 
    # that reference specific fields on auth.User. 
    list_display = ('name', 'skills', 'is_admin') 
    list_filter = ('is_admin',) 
    fieldsets = (
     (None, {'fields': ('name', 'password')}), 
     ('Personal info', {'fields': ('skills',)}), 
     ('Permissions', {'fields': ('is_admin',)}), 
    ) 
    # add_fieldsets is not a standard ModelAdmin attribute. UserAdmin 
    # overrides get_fieldsets to use this attribute when creating a user. 
    add_fieldsets = (
     (None, { 
      'classes': ('wide',), 
      'fields': ('name', 'skills', 'password1', 'password2')} 
     ), 
    ) 
    search_fields = ('name',) 
    ordering = ('name',) 
    filter_horizontal =() 


# Now register the new UserAdmin... 
admin.site.register(Freelancer, FreelancerAdmin) 
# ... and, since we're not using Django's built-in permissions, 
# unregister the Group model from admin. 
admin.site.unregister(Group) 

回答

2

您需要設置AUTH_USER_MODEL設置爲指向你的自由職業者階層,所以Django知道不加載默認的用戶模型。

此外,對於自由職業者來說,OneToOne對用戶沒有任何意義;這是該型號的替換件

+0

首先三江源先生,它的工作......但現在我得到這些錯誤 login.Freelancer .groups:(fields.E331)Field通過模型「login.Freelancer_groups」指定了一個多對多關係,該關係尚未安裝。 login.Freelancer.user_permissions:(fields.E331)字段通過模型「login.Freelancer_user_permissions」指定多對多關係,該關係尚未安裝。 message_board.Post.author:(fields.E301)字段定義與模型'auth.User'的關係,該模型已被換出。提示:更新關係以指向'設置。AUTH_USER_MODEL」。 –

+0

請回答? –

0

只是從你的整個代碼

from django.contrib.auth.models import User 

刪除下面一行,並嘗試導入自定義的usermodel