PHP - 使用搜索欄

Question

$search_exploded = explode (" ", $search); 
foreach($search_exploded as $search_each){ 
    $x++; 
    if($x==1) 
     $construct .="concat_ws(Name, Summary, Description, OpeningHours, Address, Postcode, Keywords) LIKE '%$search_each%' "; 
    else 
     $construct .="AND concat_ws(Name, Summary, Description, OpeningHours, Address, Postcode, Keywords) LIKE '%$search_each%' "; 
} 

$construct ="SELECT * FROM Rating, Attraction WHERE $construct" ; 
$run = mysql_query($construct); 
$foundnum = mysql_num_rows($run); 

if ($foundnum==0) 
    echo "Sorry, there are no matching result for '$search'" ; 
else 
{ 
    echo ""; 
    while($row = mysql_fetch_assoc($run)){ 
     echo '<a href="details.php?ID=' . $row['AttractionID'] . '"><img class="attractionimg" src="'. $row['ImageUrl'] . '" height="160" width="210" /></a>'; 
     echo '<div class="a-textcontain">'; 
     echo '<h2><a href="details.php?ID=' . $row['AttractionID'] . '">' . $row['Name'] . '</a></h2>'; 
     echo '<p class="a-text">' . $row['Summary'] . '</p>'; 
     echo '</div>'; 
     echo '<img class="rating" src="'. $row['RatingUrl'] . '" height="25" width="140" alt="Rating"/>'; 
     echo '<div class="aborderline"></div>'; 
     break; 
    } 
} 

---

我在我的數據庫12行數據時，重複結果。當我搜索它正常工作，但重複每個搜索結果12次。我曾嘗試過'休息';在像你可以看到上面但這然後限制搜索只有一個結果...

任何人有任何想法？

---

$ construct =「SELECT Attraction。*，Type.TypeName，Rating.RatingUrl」;

$ construct。=「FROM Attraction」;

$ construct。=「INNER JOIN Type ON Attraction.Type = Type.TypeID」;

$ construct。=「INNER JOIN Rating ON Attraction.AttractionID = Rating.AttractionID」;

$ construct。=「WHERE Attraction = $ construct」;

Answer 1

SELECT * FROM Rating, Attraction 

你做其中的Rating每行接合到Attraction每一行，結果乘以一個多表查詢。你將需要一個帶有特定連接條件的LEFT JOIN查詢，或者其他可能的東西，具體取決於意圖是什麼。

請參閱http://www.codinghorror.com/blog/2007/10/a-visual-explanation-of-sql-joins.html,http://dev.mysql.com/doc/refman/5.1/en/join.html。