與laravel動態查詢4

Question

朋友你好需要一隻手與此查詢，未能使其工作，我是新與laravel，我有3種型號：

DiscussCategory

class DiscussCategory extends Eloquent { 

protected $table = 'discuss_category'; 
protected $guarded = array('id'); 

public function status() { 
    return $this->belongsTo('Status'); 
} 

public function discuss() { 
    return $this->hasMany('Discuss'); 
} 

}

討論

class Discuss extends Eloquent { 

protected $table = 'discuss'; 
protected $guarded = array('id'); 

public function discussReplies() { 
    return $this->hasMany('DiscussReplies'); 
} 

public function discussCategory() { 
    return $this->belongsTo('DiscussCategory'); 
} 

public function users() { 
    return $this->belongsTo('Users'); 
} 

}

用戶

class Users extends Eloquent { 

protected $table = 'users'; 

protected $guarded = array('id'); 
protected $hidden = array('password'); 

public function getAuthIdentifier() { 
    return $this->getKey(); 
} 

public function getAuthPassword() { 
    return $this->password; 
} 

public function getReminderEmail() { 
    return $this->email; 
} 

public function discussReplies() { 
    return $this->hasOne('DiscussReplies'); 
} 

public function discuss() { 
    return $this->hasMany('Discuss'); 
} 

}

，這我如何努力，以顯示查詢鑑於

    @foreach($data as $category) 
       {{$category->discuss->last()->users->nickname}} 
       @endforeach 

如果你運行一個foreach設法獲取用戶，但我只想要最後一位用戶的姓名發表討論

Trying to get property of non-object 

appreciate a hand, insurance is not much, but I have little experience 

Answer 1

在你Discuss模式變革下面的方法：

public function users() { 
    return $this->belongsTo('Users'); 
} 

爲了這個（使用user不users）

public function user() { 
    // Assumed one discuss belongs to one user 
    return $this->belongsTo('Users'); // Rename Users to User and use User here 
} 

你也應該爲所有的車型例如，使用用單數名User而不是Users。