我有如下模式的數據庫: 不能添加或更新子行,外鍵約束失敗
下面的SQL創建相關的表:
-- -----------------------------------------------------
-- Table `ninikske_bioldb`.`CodingRegion`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `ninikske_bioldb`.`CodingRegion` (
`CodRegID` VARCHAR(45) NOT NULL ,
`CD_Start` INT NOT NULL ,
`CD_Stop` INT NOT NULL ,
`ORFs_ORF_ID` VARCHAR(45) NOT NULL ,
PRIMARY KEY (`ORFs_ORF_ID`, `CodRegID`) ,
INDEX `fk_Exons_ORFs1` (`ORFs_ORF_ID` ASC) ,
CONSTRAINT `fk_Exons_ORFs1`
FOREIGN KEY (`ORFs_ORF_ID`)
REFERENCES `ninikske_bioldb`.`ORFs` (`ORF_ID`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `ninikske_bioldb`.`Experiment`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `ninikske_bioldb`.`Experiment` (
`Probe_GenomicPos` INT NOT NULL ,
`SampleName` VARCHAR(45) NOT NULL ,
`Intensities` FLOAT NOT NULL ,
`ExperimentName` VARCHAR(45) NOT NULL ,
`ProbeID` INT NOT NULL ,
PRIMARY KEY (`Probe_GenomicPos`, `SampleName`, `ProbeID`))
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `ninikske_bioldb`.`CE`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `ninikske_bioldb`.`CE` (
`OrfId` VARCHAR(45) NOT NULL ,
`CodRegId` VARCHAR(45) NOT NULL ,
`GenPos` INT NOT NULL ,
`ExpSam` VARCHAR(45) NOT NULL ,
`ProbeId` INT NOT NULL ,
PRIMARY KEY (`OrfId`, `CodRegId`, `GenPos`, `ExpSam`, `ProbeId`) ,
INDEX `fk_CodingRegion_has_Experiment_Experiment1` (`GenPos` ASC, `ExpSam` ASC, `ProbeId` ASC) ,
INDEX `fk_CodingRegion_has_Experiment_CodingRegion1` (`OrfId` ASC, `CodRegId` ASC) ,
CONSTRAINT `fk_CodingRegion_has_Experiment_CodingRegion1`
FOREIGN KEY (`OrfId` , `CodRegId`)
REFERENCES `ninikske_bioldb`.`CodingRegion` (`ORFs_ORF_ID` , `CodRegID`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `fk_CodingRegion_has_Experiment_Experiment1`
FOREIGN KEY (`GenPos` , `ExpSam` , `ProbeId`)
REFERENCES `ninikske_bioldb`.`Experiment` (`Probe_GenomicPos` , `SampleName` , `ProbeID`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
當我執行通過Java下面的INSERT語句:
String query = "INSERT INTO ninikske_bioldb.CE VALUES('" + cs.getORF_ID().getORF_ID() + "','" + cs.getCodRegID().getCodRegID() + "'," + cs.getExp().getProbePos() + ",'" + cs.getExp().getExpName()+ "', " + cs.getExp().getProbeID() + ");";
Statement stmt = con.createStatement();
stmt.executeUpdate(query);
我得到以下錯誤:
Cannot add or update a child row: a foreign key constraint fails (`ninikske_bioldb/CE`, CONSTRAINT `fk_CodingRegion_has_Experiment_Experiment1` FOREIGN KEY (`GenPos`, `ExpSam`, `ProbeId`) REFERENCES `Experiment` (`Probe_GenomicPos`, `SampleName`, `ProbeID`))
我讀了幾個關於同樣的錯誤信息的其他問題,但我似乎無法找到我需要的洞察力。
編輯 查詢是: INSERT INTO ninikske_bioldb.CE VALUES('AT3G01190.1','cd474',67262,'H20', 1709);
當我檢查我的父表,我得到以下結果:提前
mysql> SELECT * FROM CodingRegion WHERE ORFs_ORF_ID = 'AT3G01190.1';
+----------+----------+---------+-------------+
| CodRegID | CD_Start | CD_Stop | ORFs_ORF_ID |
+----------+----------+---------+-------------+
| cd474 | 67243 | 67649 | AT3G01190.1 |
| cd475 | 67733 | 67892 | AT3G01190.1 |
| cd476 | 67991 | 68176 | AT3G01190.1 |
| cd477 | 68272 | 68484 | AT3G01190.1 |
+----------+----------+---------+-------------+
4 rows in set (0.00 sec)
mysql> SELECT * FROM CodingRegion WHERE CodRegID = 'cd474';
+----------+----------+---------+-------------+
| CodRegID | CD_Start | CD_Stop | ORFs_ORF_ID |
+----------+----------+---------+-------------+
| cd474 | 67243 | 67649 | AT3G01190.1 |
+----------+----------+---------+-------------+
1 row in set (0.03 sec)
mysql> SELECT * FROM Experiment WHERE Probe_GenomicPos = '67262';
+------------------+--------------+-------------+----------------+---------+
| Probe_GenomicPos | SampleName | Intensities | ExperimentName | ProbeID |
+------------------+--------------+-------------+----------------+---------+
| 67262 | 1signalpart1 | 8.94432 | H20 | 1709 |
+------------------+--------------+-------------+----------------+---------+
1 row in set (0.00 sec)
mysql> SELECT * FROM Experiment WHERE SampleName = 'H20'
Empty set (0.00 sec)
mysql> SELECT * FROM Experiment WHERE ProbeID = '1709';
+------------------+--------------+-------------+----------------+---------+
| Probe_GenomicPos | SampleName | Intensities | ExperimentName | ProbeID |
+------------------+--------------+-------------+----------------+---------+
| 67262 | 1signalpart1 | 8.94432 | H20 | 1709 |
+------------------+--------------+-------------+----------------+---------+
1 row in set (0.00 sec)
感謝。
是否所有您插入的ID都存在於父表中? – gmadd 2011-05-13 15:56:50
和'String query'的輸出是什麼? – gmadd 2011-05-13 16:09:09
@gmadd看我的編輯。 – BioGeek 2011-05-13 16:23:59