解析URL哈希與正則表達式

Question

需要解析字符串

#Login&oauth_token=theOAUTHtoken&oauth_verifier=12345 

在哪裏我只需要得到oauth_token和oauth_verifier鍵+值，什麼是正則表達式來做到這一點最簡單的方法是什麼？

Answer 1

這將做到這一點，你沒有指定你怎麼想你的數據輸出，所以我分隔用逗號將它們。

import java.util.regex.*; 

class rTest { 
    public static void main (String[] args) { 
    String in = "#Login&oauth_token=theOAUTHtoken&oauth_verifier=12345"; 
    Pattern p = Pattern.compile("(?:&([^=]*)=([^&]*))"); 
    Matcher m = p.matcher(in); 
    while (m.find()) { 
     System.out.println(m.group(1) + ", " + m.group(2)); 
    } 
    } 
} 

正則表達式：

(?:   group, but do not capture: 
    &   match '&' 
    (   group and capture to \1: 
    [^=]*  any character except: '=' (0 or more times) 
    )   end of \1 
    =   match '=' 
    (   group and capture to \2: 
    [^&]*  any character except: '&' (0 or more times) 
    )   end of \2 
)    end of grouping 

輸出：

oauth_token, theOAUTHtoken 
oauth_verifier, 12345 

Answer 2

這應該工作：

String s = "#Login&oauth_token=theOAUTHtoken&oauth_verifier=12345"; 
Pattern p = Pattern.compile("&([^=]+)=([^&]+)"); 
Matcher m = p.matcher(s.substring(1)); 
Map<String, String> matches = new HashMap<String, String>(); 
while (m.find()) { 
    matches.put(m.group(1), m.group(2)); 
} 
System.out.println("Matches => " + matches); 

OUTPUT：

Matches => {oauth_token=theOAUTHtoken, oauth_verifier=12345}