如何使用之前調用的數據進行第二次JS .post調用？

Question

所以，我有一個JS .post調用，通過控制器操作向表中添加一行。然後它將該行的主鍵返回到視圖。我需要將這個整數插入到第二個.post調用的數據中，我需要對另一個控制器進行調用。

更新的Javascript 首先來看看我的javascript：

var result = $.post('/Question/CreateSimpleQuestion/', (data), function (result) { 
            $.post('/Question/CreateSimpleQuestionChoice/', ({ 
                   "QuestionId":result, 
                   "DisplayText": text, 
                   "OrderNumber": order, 
                   "is_correct": false}), 
                    null, 'application/json'); 
       }, 'application/json'); 

這些是被稱爲控制器操作：

 // 
    // POST: /Question/CreateSimpleQuestion 

    [HttpPost] 
    public JsonResult CreateSimpleQuestion(Question question) 
    { 
     question.is_counted = true; 
     question.DateCreated = DateTime.Now; 
     db.Questions.Add(question); 
     db.SaveChanges(); 
     return Json(question.QuestionId, JsonRequestBehavior.AllowGet); 
    } 

    // 
    // POST: /Question/CreateSimpleQuestion 

    [HttpPost] 
    public JsonResult CreateSimpleQuestionChoice(QuestionChoices choice) 
    { 
     db.QuestionChoices.Add(choice); 
     db.SaveChanges(); 

     return Json(choice, JsonRequestBehavior.AllowGet); 
    } 

Answer 1

你第Ajax調用創建成功處理程序（鑰匙可用的地方），並且在該成功處理程序中，您將進行第二次ajax調用，然後您可以將該密鑰傳遞給它。

var result = $.post('/Question/CreateSimpleQuestion/', data, function(result) { 
    // make your second ajax call here and you can use the result of the first 
    // ajax call here 
    var dataq = { 
     "QuestionId": result.QuestionId, // data from first ajax call here 
     "DisplayText": text, 
     "OrderNumber": order, 
     "is_correct": false 
    }; 
    $.post('/Question/CreateSimpleQuestionChoice/', dataq, function(result2) { 
     // examine result of second ajax function here 
     // code goes here 
    }, 'application/json'); 

}, 'application/json'); 

---

下面是與嵌入，所以你可以跟蹤它在調試控制檯的進步，但我個人更喜歡只設置斷點和檢查變量控制檯調試語句的版本。

console.log("Position 1"); 
console.log(data); 
var result = $.post('/Question/CreateSimpleQuestion/', data, function(result) { 
    // make your second ajax call here and you can use the result of the first 
    // ajax call here 
    var dataq = { 
     "QuestionId": result.QuestionId, // data from first ajax call here 
     "DisplayText": text, 
     "OrderNumber": order, 
     "is_correct": false 
    }; 
    console.log("Position 2"); 
    console.log(dataq); 
    $.post('/Question/CreateSimpleQuestionChoice/', dataq, function(result2) { 
     // examine result of second ajax function here 
     // code goes here 
     console.log("Position 3"); 
     console.log(result2); 
    }, 'application/json'); 

}, 'application/json');