我有一個父頁面,充當我的投資組合的菜單。子頁面內容
它從我已經能夠用魔術字段和一些代碼完成的子頁面中縮略圖。它將圖像轉儲爲網格佈局。縮略圖被拉入一個容器DIV像這樣:
div id="folio-content">
<div class="thumb-container">
<div class="thumb"><img src="/images/pic.jpg"/>
</div>JCPenny</div>
... </div>`
當DIV獲取與2個縮略圖填補我想創建一個新的div容器,並再次等後2個圖像與2個圖像填充它。
所以,如果你有4個圖像,它會看起來像這樣。
<div id="folio-content"><!--/Main Container/-->
<div class="thumb-container">
<div class="thumb"><img src="/images/pic1.jpg"/>
</div>JCPenny</div>
<div class="thumb-container">
<div class="thumb"><img src="/images/pic1.jpg"/>
</div>Champ Car</div></div>
<div id="folio-content"><!--/Main Container/-->
<div class="thumb-container">
<div class="thumb"><img src="/images/pic1.jpg"/>
</div>JCPenny</div>
<div class="thumb-container">
<div class="thumb"><img src="/images/pic1.jpg"/>
</div>Champ Car</div></div>
this is the code I am using in my page.php file.
<?php get_header(); ?>
<div id="folio-content">
<?php
$projectpage = get_pages('child_of='.$post->ID.'&sort_column=post_date&sort_order=desc');
$count = 0;
foreach($projectpage as $page)
{
$content = $page->post_content;
if(!$content)
continue;
if ($count == 10) --- this is geting 10 images now, but I want to get them all.
break;
$count++;
$content = apply_filters('the_content', $content);
?>
<div class="thumb-container">
<div class="thumb"><a href="<?php echo get_permalink($page->ID); ?>"<?php echo get_image ("thumbnail",1,1,1,$page->ID);?></a>
</div><?php echo $page->post_title ?>
</div>
<?php
}
?>
</div><!--/close set!-->
</div>
另外,我怎麼能得到所有的子頁面?我已經設置爲10現在這個if ($count == 10)
任何幫助嗎?再次感謝噸!
謝謝!這段代碼很好,得到所有的子頁面...所以我解決了..謝謝! – chad 2010-12-13 17:20:46