iOS：獲取公共賬戶的推特供稿

Question

我需要獲取公共賬戶的推文供稿。我可以用下面的代碼，讓我自己的Twitter飼料：

-(void) testTwitter { 
{ 
    ACAccountStore *accountStore = [[ACAccountStore alloc]init]; 

    if (accountStore != nil) 
    { 
     ACAccountType *accountType = [accountStore  accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter]; 
     if (accountType != nil) 
     { 
      [accountStore requestAccessToAccountsWithType:accountType options:nil completion:^(BOOL granted, NSError *error) 
      { 
       if (granted) 
       { 

        //Succesful Access 
        NSArray *twitterAccounts = [accountStore accountsWithAccountType:accountType]; 
        if (twitterAccounts != nil) 
        { 
         ACAccount *currentAccount = [twitterAccounts objectAtIndex:0]; 
         if (currentAccount != nil) 
         { 
          NSString *paraString = [NSString stringWithFormat:@"qlx_corp"]; 
          NSDictionary *parameters = [NSDictionary dictionaryWithObject:paraString forKey:@"username"]; 

          NSString *requestString = @"https://api.twitter.com/1.1/statuses/user_timeline.json"; 
          SLRequest *request = [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodGET URL:[NSURL URLWithString:requestString] parameters:parameters]; 
          [request setAccount:currentAccount]; 

          [request performRequestWithHandler:^(NSData *responseData, NSHTTPURLResponse *urlResponse, NSError *error) 
           { 
            if ((error == nil) && ([urlResponse statusCode] == 200)) 
            { 
             NSArray *twitterFeed = [NSJSONSerialization JSONObjectWithData:responseData options:0 error:nil]; 
             NSDictionary *firstPost = [twitterFeed objectAtIndex:0]; 

             NSLog(@"firstPost = %@", [firstPost description]); 
            } 
            else { 
             NSLog(@"error: %@",error); 
            } 
           }]; 
         } 
        } 
       } 
       else 
       { 
        //Access Denied 
        NSLog(@"access denied"); 
       } 
      }]; 
     } 
    } 

} 
} 

但是，當我替換下面的代碼用於獲取帳戶以外我自己，我得到這個錯誤：

碼= 215;

message =「Bad Authentication data。」;

這是我代替一個成功的接入代碼（在發佈代碼中的註釋說明）：

NSURL* url = [NSURL URLWithString:@"https://api.twitter.com/1.1/statuses/user_timeline.json"]; 
        NSDictionary* params = @{@"count" : @"10", @"screen_name" : @"qlx_corp"}; 

        SLRequest *request = [SLRequest requestForServiceType:SLServiceTypeTwitter 
                  requestMethod:SLRequestMethodGET 
                     URL:url parameters:params]; 

        [request performRequestWithHandler:^(NSData *responseData, 
                  NSHTTPURLResponse *urlResponse, NSError *error) { 

         if (!error) { 
          NSError *jsonError; 
         NSArray *responseJSON = [NSJSONSerialization 
                JSONObjectWithData:responseData 
                options:NSJSONReadingAllowFragments 
                error:&jsonError]; 
          NSLog(@"response json: %@",responseJSON); 
         // Show the content of the responseJSON in a view. 
        } 
         }]; 

什麼我做錯了，我收到此錯誤信息，而不是公共Twitter的飼料我正在請求。我的應用程序要求獲得Twitter使用許可，並已獲得批准，那麼可能是什麼問題？

Answer 1

我最終使用Twitter API，因爲現在它們支持不需要用戶身份驗證來顯示公共Twitter提要的僅應用程序模式。請參閱此鏈接瞭解更多信息：Twitter OAuth and accessToken to GET statuses/user_timeline in Objective-C