通過ID調用db行但向後

Question

我正在建立一個鏈接投票站點，該公式工作正常後，鏈接投票第二次，問題是，當鏈接只有1票它顯示了倒退，從最舊到最新。

我想要的是帶有一個投票的鏈接顯示從最新到最舊。這是調用在頭版的鏈接線：

$articles = Article::getAll("order by ranking desc limit $offset, $num_items"); 

這是GETALL功能代碼：

static function getAll($conditions = ' ') 
    { 
     /* Retrieve all the records from the 
     * database according subject to 
     * conditions 
     */ 

     $db = null; 
     $results = null; 
     $records = array(); 
     $query = "select id, created, modified, username, url, title, description, points, ranking from articles $conditions"; 
     try 
     { 
      $db = parent::getConnection(); 
      $results = parent::execSql($query); 

      while($row = $results->fetch_assoc()) 
      { 
       $r_id = $row['id']; 
       $r_created = $row['created']; 
       $r_modified = $row['modified']; 

       $r_title = $row['title']; 
       $r_description = $row['description']; 

       if(!get_magic_quotes_gpc()) 
       { 
        $r_title = stripslashes($r_title); 
        $r_description = stripslashes($r_description); 
       } 

       $r_url = $row['url']; 
       $r_username = $row['username']; 
       $r_points = $row['points']; 
       $r_ranking = $row['ranking']; 

       $article = new Article($r_title, $r_description , $r_url, $r_username, $r_created, $r_modified); 
       $article->id = $r_id; 
       $article->points = $r_points; 
       $article->ranking = $r_ranking; 
       $records[] = $article; 
      } 
      parent::closeConnection($db); 
     } 
     catch(Exception $e) 
     { 
      throw $e; 
     } 

     return $records; 
    } 

如果有人可以幫助我將不勝感激。

Answer 1

我會做大衛說什麼，只是，如果你想通過最新的第一個命令的鏈接，那麼你必須按降序添加了「創建」列：

$articles = Article::getAll("order by ranking desc, created DESC limit $offset, $num_items"); 

Answer 2

將created日期添加到order子句怎麼樣？

$articles = Article::getAll("order by ranking desc, created desc limit $offset, $num_items");