剛剛開始學習功能,並有一個很好的把握,他們感謝這個線程我張貼Passing variable through switch statement with functions。隨機骰子游戲使用功能
創建一個骰子游戲這樣做,但我有麻煩。它似乎應該比我問的前一個問題更容易,但事實並非如此。我無法通過函數傳遞三個隨機骰子。另外,如預期的那樣,我最後的陳述並不奏效,但我不知道爲什麼。這是我目前的看法。對不起,我不喜歡我的令人討厭的菜單名稱
#include<stdlib.h>
#include<stdio.h>
#include <time.h>
#include <ctype.h>
#define MAXROLLS 5
#define LOWERBOUND 1
#define UPPERBOUND 6
#define PAUSE system("pause")
int diceOne, diceTwo, diceThree;
int currentDiceSum=0, totalDiceSum=0;
int quit= 0;
int count = 0;
char menuChoice()
{
char choice;
printf("\n\n==============================================================================\n");
printf("\n\n== W E L C O M E T O M Y D I C E R O L L I N G G A M E==\n");
printf("\n\n==============================================================================\n");
printf("\n Roll the dice, but you only get 5 rolls! You can't play forever, you know. \n");
printf("Main Menu\n");
printf("A.Roll the Dice\n");
printf("B.Display the Result of Last Roll\n");
printf("C.Quit\n");
printf("Enter your choice: ");
scanf(" %c", &choice);
choice = toupper(choice);
}
int rollTheDice()
{
int diceOne = LOWERBOUND + rand() % (UPPERBOUND - LOWERBOUND + 1);
int diceTwo = LOWERBOUND + rand() % (UPPERBOUND - LOWERBOUND + 1);
int diceThree = LOWERBOUND + rand() % (UPPERBOUND - LOWERBOUND + 1);
srand((unsigned)time(NULL));
return diceOne;
return diceTwo;
return diceThree;
}
int getDiceRoll()
{
currentDiceSum = diceOne + diceTwo + diceThree;
totalDiceSum+= currentDiceSum;
}
int quitTotal()
{
totalDiceSum+= currentDiceSum;
}
int main()
{
while(quit!=1) //begin menu loop
{
char menu;
menu = menuChoice();
switch(menu)
{
case 'A':
{
rollTheDice();
printf("Dice are rolled!\n");
count++;
printf("You have %i rolls left.\n", MAXROLLS - count);
break;
}
case 'B':
getDiceRoll();
printf("Dice 1: %d\n", diceOne);
printf("Dice 2: %d\n", diceTwo);
printf("Dice 2: %d\n", diceThree);
printf("Dice Total: %d\n", currentDiceSum);
break;
case 'C':
quitTotal();
printf("Number of rolls: %d\n", count);
printf("Total of all dice for all rolls: %d\n", totalDiceSum);
printf("Goodbye, hope to see you again!!!\n");
PAUSE;
quit = 1;
break;
default:
printf("Please enter A,B,C\n");
break;
} //end switch
} // end loop
if (count == MAXROLLS)
{
printf("Sorry, your rolls are up!!!\n");
printf("Your final roll was:\n");
printf("Dice 1: %d\n", diceOne);
printf("Dice 2: %d\n", diceTwo);
printf("Dice 3: %d\n", diceThree);
currentDiceSum = diceOne + diceTwo + diceThree;
printf("Your final dice sum was\n");
printf("Dice Total: %d\n", currentDiceSum);
totalDiceSum+= currentDiceSum;
printf("Number of rolls: %d\n", count);
printf("Total of all dice for all rolls: %d\n", totalDiceSum);
printf("Goodbye, hope to see you again!!!\n");
}
} //end function
截至目前我在一個迷路。我相信每個函數只能返回一個結果。所以也許我需要爲每個骰子創建三個獨立的函數?
typedef struct{
int diceOne;
int diceTwo;
int diceThree;
}DiceRolls;
DiceRolls rollTheDice()
{
DiceRolls dice;
dice.diceOne = LOWERBOUND + rand() % (UPPERBOUND - LOWERBOUND + 1);
dice.diceTwo = LOWERBOUND + rand() % (UPPERBOUND - LOWERBOUND + 1);
dice.diceThree = LOWERBOUND + rand() % (UPPERBOUND - LOWERBOUND + 1);
return dice;
}
每下面的評論,建議在調用srand()
在初始化過程中只有一次完成:
你不需要「返回」他們,只是不要*聲明他們在那個函數中 - 他們已經是全局的。 (另外,查看'srand'的一些文檔,因爲它沒有多大用處。) – usr2564301
你是否已經瞭解了有關數組的知識?如果是這樣,請考慮'int dice [3]的優點;'作爲你的變量。 –