我想從.net Web服務使用方法。KSOAP2 java.lang.RuntimeException:無法序列化
落後於Web服務的代碼在命名空間
[WebService(Namespace = "http://www.mynamespace.com/")]
[WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]
這裏的盡頭有個「/」是.NET方法調用
POST /TelematicsWebService/Service.asmx HTTP/1.1
Host: localhost
Content-Type: text/xml; charset=utf-8
Content-Length: length
SOAPAction: "http://www.mynamespace.com/GetDevicesByBranch"
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Body>
<GetDevicesByBranch xmlns="http://www.mynamespace.com/">
<branchNumber>int</branchNumber>
</GetDevicesByBranch>
</soap:Body>
</soap:Envelope>
現在代碼調用方法如下像這樣
@Override
protected SoapObject doInBackground(Integer... branchNumber) {
final String NAMESPACE = "http://www.mynamespace.com/";
final String METHOD_NAME = "GetDevicesByBranch";
final String SOAP_ACTION = NAMESPACE + METHOD_NAME;
final String URL = "http://10.0.2.2/TelematicsWebService/Service.asmx";
SoapObject response = null;
try {
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
PropertyInfo inputArgs = new PropertyInfo();
inputArgs.setName("branchNumber");
inputArgs.setValue(branchNumber);
inputArgs.setType(Integer.class);
request.addProperty(inputArgs);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL,
25000);
androidHttpTransport.call(SOAP_ACTION, envelope);
response = (SoapObject) envelope.getResponse();
} catch (Exception exception) {
response = null;
}
return response;
}
接近尾聲的行androidHttpTransport.call(SOAP_ACTION, envelope);
引發異常:java.lang.RuntimeException: Cannot serialize: [Ljava.lang.Integer;@412e0cf0
我找不到解決此問題的建議嗎?
完全錯過了,謝謝分享!我刪除了我的答案,因爲除了沒有幫助,事實上是錯誤的。 – 2012-08-11 08:03:16