在Eclipse樹狀查看器中單獨選擇樹節點

Question

我有一段代碼和一個樹查看器作爲eclipse插件的一部分。該代碼是在這裏（這是直接從Eclipse的PDE樣品樹視圖拍攝）：

public class SampleView extends ViewPart { 

    /** 
    * The ID of the view as specified by the extension. 
    */ 
    public static final String ID = "com.test2.views.SampleView"; 

    private TreeViewer viewer; 
    private DrillDownAdapter drillDownAdapter; 
    private Action action1; 
    private Action action2; 
    private Action doubleClickAction; 

    /* 
    * The content provider class is responsible for 
    * providing objects to the view. It can wrap 
    * existing objects in adapters or simply return 
    * objects as-is. These objects may be sensitive 
    * to the current input of the view, or ignore 
    * it and always show the same content 
    * (like Task List, for example). 
    */ 

    class TreeObject implements IAdaptable { 
     private String name; 
     private TreeParent parent; 

     public TreeObject(String name) { 
      this.name = name; 
     } 
     public String getName() { 
      return name; 
     } 
     public void setParent(TreeParent parent) { 
      this.parent = parent; 
     } 
     public TreeParent getParent() { 
      return parent; 
     } 
     public String toString() { 
      return getName(); 
     } 
     public Object getAdapter(Class key) { 
      return null; 
     } 
    } 

    class TreeParent extends TreeObject { 
     private ArrayList children; 
     public TreeParent(String name) { 
      super(name); 
      children = new ArrayList(); 
     } 
     public void addChild(TreeObject child) { 
      children.add(child); 
      child.setParent(this); 
     } 
     public void removeChild(TreeObject child) { 
      children.remove(child); 
      child.setParent(null); 
     } 
     public TreeObject [] getChildren() { 
      return (TreeObject [])children.toArray(new TreeObject[children.size()]); 
     } 
     public boolean hasChildren() { 
      return children.size()>0; 
     } 
    } 

    class ViewContentProvider implements IStructuredContentProvider, 
              ITreeContentProvider { 
     private TreeParent invisibleRoot; 

     public void inputChanged(Viewer v, Object oldInput, Object newInput) { 
     } 
     public void dispose() { 
     } 
     public Object[] getElements(Object parent) { 
      if (parent.equals(getViewSite())) { 
       if (invisibleRoot==null) initialize(); 
       return getChildren(invisibleRoot); 
      } 
      return getChildren(parent); 
     } 
     public Object getParent(Object child) { 
      if (child instanceof TreeObject) { 
       return ((TreeObject)child).getParent(); 
      } 
      return null; 
     } 
     public Object [] getChildren(Object parent) { 
      if (parent instanceof TreeParent) { 
       return ((TreeParent)parent).getChildren(); 
      } 
      return new Object[0]; 
     } 
     public boolean hasChildren(Object parent) { 
      if (parent instanceof TreeParent) 
       return ((TreeParent)parent).hasChildren(); 
      return false; 
     } 
/* 
* We will set up a dummy model to initialize tree heararchy. 
* In a real code, you will connect to a real model and 
* expose its hierarchy. 
*/ 
     private void initialize() { 
      TreeObject to1 = new TreeObject("Leaf 1"); 
      TreeObject to2 = new TreeObject("Leaf 2"); 
      TreeObject to3 = new TreeObject("Leaf 3"); 
      TreeParent p1 = new TreeParent("Parent 1"); 
      p1.addChild(to1); 
      p1.addChild(to2); 
      p1.addChild(to3); 

      TreeObject to4 = new TreeObject("Leaf 4"); 
      TreeParent p2 = new TreeParent("Parent 2"); 
      p2.addChild(to4); 

      TreeParent root = new TreeParent("Root"); 
      root.addChild(p1); 
      root.addChild(p2); 

      invisibleRoot = new TreeParent(""); 
      invisibleRoot.addChild(root); 
     } 
    } 
    class ViewLabelProvider extends LabelProvider { 

     public String getText(Object obj) { 
      return obj.toString(); 
     } 
     public Image getImage(Object obj) { 
      String imageKey = ISharedImages.IMG_OBJ_ELEMENT; 
      if (obj instanceof TreeParent) 
       imageKey = ISharedImages.IMG_OBJ_FOLDER; 
      return PlatformUI.getWorkbench().getSharedImages().getImage(imageKey); 
     } 
    } 
    class NameSorter extends ViewerSorter { 
    } 

    /** 
    * The constructor. 
    */ 
    public SampleView() { 
    } 

    /** 
    * This is a callback that will allow us 
    * to create the viewer and initialize it. 
    */ 
    public void createPartControl(Composite parent) { 
     viewer = new TreeViewer(parent, SWT.MULTI | SWT.H_SCROLL | SWT.V_SCROLL); 
     drillDownAdapter = new DrillDownAdapter(viewer); 
     viewer.setContentProvider(new ViewContentProvider()); 
     viewer.setLabelProvider(new ViewLabelProvider()); 
     viewer.setSorter(new NameSorter()); 
     viewer.setInput(getViewSite()); 

     // Create the help context id for the viewer's control 
     PlatformUI.getWorkbench().getHelpSystem().setHelp(viewer.getControl(), "com.test2.viewer"); 
     makeActions(); 
     hookContextMenu(); 
     hookDoubleClickAction(); 
     contributeToActionBars(); 
    } 

我想以某種方式能夠單獨通過所有節點走在樹和控制方式，他們正在展開或摺疊。基本上我只想知道如何能夠遍歷樹上的所有節點來單獨調整設置。

這應該是一個簡單的問題，但我似乎還沒有找到任何可行的方法... 我想弄清楚TreeViewer對象的getItem（）是如何工作的。但是問題是即使我得到這個項目，我也無法（或者不確定如何）修改它。

感謝所有幫助

Answer 1

首先得到觀衆的基本樹：

Tree tree = viewer.getTree(); 

然後獲得在樹中的第一級項目：

TreeItem[] item = tree.getItems(); 

任何樹項目可以回答它的所有直接子女：

TreeItem[] item = aTreeItem.getItems(); 

一旦你得到一個樹項目，可以展開或摺疊：

aTreeItem.setExpanded(true); 

所以訪問所有的樹項目的必須是遞歸的。