1
所以我嘗試使用我的代碼時出現此錯誤。我不明白爲什麼我會得到這個:TypeError:'builtin_function_or_method'對象不是可訂閱的
File "/Users/max/Desktop/Code/Python/game.py", line 30, in <module>
lineone.remove[0] #or whatever number I use
TypeError: 'builtin_function_or_method' object is not subscriptable
我的代碼是
lineone = ['0', '0', '0', '0', '0', '0', '0']
linetwo = ['0', '0', '0', '0', '0']
linethree = ['0', '0', '0']
lineoneX = ['X', 'X', 'X', 'X', 'X', 'X', 'X']
linetwoX = ['X', 'X', 'X', 'X', 'X']
linethreeX = ['X', 'X', 'X']
notfirst = 0
player1 = input('''Enter player 1's name ''')
player2 = input('''Enter player 2's name ''')
print('The person who takes the last stone wins!')
print(lineone[0], lineone[1], lineone[2], lineone[3], lineone[4], lineone[5], lineone[6])
print(linetwo[0], linetwo[1], linetwo[2], linetwo[3], linetwo[4])
print(linethree[0], linethree[1], linethree[2])
while True:
#WTD means -What to Delete
WTD = input('Type the row number, then the amount of stones you want to take, in the format 1, 1. ')
# Line One
if WTD == '1, 1':
lineone.remove[0]
if WTD == '1, 2':
lineone.remove[1]
if WTD == '1, 3':
lineone.remove[2]
if WTD == '1, 4':
lineone.remove[3]
if WTD == '1, 5':
lineone.remove[4]
if WTD == '1, 6':
lineone.remove[5]
if WTD == '1, 7':
lineone.remove[6]
# Line Two
if WTD == '2, 1':
linetwo.remove[0]
if WTD == '2, 2':
linetwo.remove[1]
if WTD == '2, 3':
linetwo.remove[2]
if WTD == '2, 4':
linetwo.remove[3]
if WTD == '2, 5':
linetwo.remove[4]
# Line Three
if WTD == '3, 1':
linetwo.remove[0]
if WTD == '3, 2':
linetwo.remove[1]
if WTD == '2, 3':
linetwo.remove[2]
print(lineone)
print(linetwo)
print(linethree)
我已經看着很多其他地方,但我不明白,爲什麼這是行不通的。我正在使用方括號,我爲第一項使用0而不是1。 所以請幫助, 在此先感謝!
'remove'是一種方法;你用括號括起來而不是括號。它也沒有做你想做的事情,所以你在改變方括號後仍然會遇到問題。 – user2357112
你是什麼意思:它也沒有做你想做的事 – Maximus
你試圖從列表中刪除指定數量的項目。 '刪除'不這樣做。 – user2357112