檢查連續號碼的Java方法

Question

我需要編寫一個稱爲連續的方法，它需要6個參數來檢查6個輸入是否是連續的數字，而不管順序如何。如果數字是連續的，則返回true，否則返回false。有人能教我什麼是最有效的方法嗎？我試過這種方法，但如果我有6個數字，效率會很低？

public static boolean consecutive(int numberOne,int numberTwo,int numberThree) { 
    if(((numberTwo==numberOne-1) && (numberThree== numberTwo-1)) || ((numberTwo==numberOne+1) && (numberThree==numberTwo+1)) || ((numberTwo==numberOne+2) &&(numberThree==numberOne+1)) || ((numberTwo==numberOne-1)&& (numberThree==numberOne+1)) || ((numberTwo==numberOne-2) && (numberThree==numberOne-1)) ||((numberTwo==numberOne+1) && (numberThree==numberOne-1))){ 
     return true; 
    }else{ 
     return false; 
    } 
} 

} 

Answer 1

值添加到一個數組，數組排序，然後測試順序組值：

int[] test = new int[] {numberOne, numberTwo, etc...}; 
Arrays.sort(test); 
for (int i = 0; i < test.length - 1; i++) { 
    if (test[i] + 1 != test[i + 1]) { 
    // Not sequential 
    } 
} 

Answer 2

加強@克里斯的回答，假設沒有重複號碼：

public static boolean consecutive(
    int numberOne,int numberTwo,int numberThree, 
    int numberFour, int numberFive, int numberSix) { 

int [] ns = { 
    numberOne, numberTwo, numberThree, 
    numberFour, numberFive, numberSix }; 

Arrays.sort(ns); 

return (ns[ns.length-1] - ns[0] == ns.length-1); 
}