刪除正則表達式匹配

Question

我有一個程序，我需要能夠使用正則表達式來搜索文件並刪除正則表達式找到的內容。這是我一直在努力代碼：

#include <boost/regex.hpp> 
#include <iostream> 
#include <string> 
#include <fstream> 
#include <sstream> 
#include "time.h" 
using namespace std; 


class application{ 
private: 
//Variables 
boost::regex expression; 
boost::smatch matches; 
string line; 
string pat; 
int lineNumber; 
string replace; 
char time[9]; 
char date[9]; 

//Functions 
void getExpression(){ 
    cout << "Expression: "; 
    cin >> pat; 
    try{ 
    expression = pat; 
    } 
    catch(boost::bad_expression){ 
    cout << pat << " is not a valid regular expression\n"; 
    exit(1); 
    } 
} 

void boostMatch(){ 
    //Files to open 
    //Input Files 
    ifstream in("files/trff292010.csv"); 
    if(!in) cerr << "no file\n"; 
    //Output Files 
    ofstream out("files/ORIGtrff292010.csv"); 
    ofstream newFile("files/NEWtrff292010.csv"); 
    ofstream record("files/record.dat"); 
    //time 
    _strdate_s(date); 
    _strtime_s(time); 
    lineNumber = 0; 

    while(in.peek() != EOF){ 
    getline(in, line, '\n'); 
    lineNumber++; 
    out << line << "\n"; 
    if (regex_search(line, matches, expression)){ 
    for (int i = 0; i<matches.size(); ++i){ 

    record << "Date: "<< date << "Time: " << time << "\tmatches[" << i << "]: " << matches[i] << "\n\tLine Number: "<< lineNumber<< '\n\t\t' << line << '\n'; 
    boost::regex_replace(line, expression, ""); 
    newFile << line << "\n"; 
    } 
    }else{ 
    newFile << line << "\n"; 
    } 
    } 
} 

public: 
void run(){ 
    replace = ""; 
    getExpression(); 
    boostMatch(); 
} 
}; 

正如你看到的我是想使用boost :: regex_replace只需更換什麼發現有空格，但沒有奏效。我一直在運行的測試是使用[*]查找列表中某些名稱前的所有星號。示例*愛麗絲。該程序確實找到了明星，但並沒有刪除只是愛麗絲

Answer 1

看起來的boost :: regex_replace返回一個字符串，而不是修改輸入。見the documentation for this method。

試試這個：

newFile << boost::regex_replace(line, expression, "") << "\n"; 

Answer 2

逃脫與* \ *。

Answer 3

這是一個相當普遍的問題， http://bytes.com/topic/c/answers/166133-problem-boost-regex_replace

也許上面的鏈接有助於