MySQL的 - 連勝

Question

嗨，我試圖找出找到最大的連勝紀錄在我的表中的每個成員的一種方式。當桌子建成時，這從來沒有出現在計劃中，所以我爲什麼尋求幫助來實現這一目標。

我的結構如下：

id player_id opponant_id  won  loss timestamp 

如果它是一個人的遊戲中，玩家ID是他們的ID。如果他們受到某人的挑戰，他們的id是opponant id，贏得的損失（1或0）與player_id有關。

我想找到每個用戶的最大連勝。

人對如何與當前的表結構做任何想法。

問候

編輯

下面是一些測試數據，其中id 3是玩家的問題：

id player_id won  loss timestamp 
1 6   0  1  2012-03-14 13:31:00 
13 3   0  1  2012-03-15 13:10:40 
17 3   0  1  2012-03-15 13:29:56 
19 4   0  1  2012-03-15 13:37:36 
51 3   1  0  2012-03-16 13:20:05 
53 6   0  1  2012-03-16 13:32:38 
81 3   0  1  2012-03-21 13:14:49 
89 4   1  0  2012-03-21 14:01:28 
91 5   0  1  2012-03-22 13:14:20 

Answer 1

試試這個。 編輯，因爲它經過考慮到損失的行

SELECT 
    d.player_id, 
    MAX(d.winStreak) AS maxWinStreak 
FROM (
    SELECT 
     @cUser := 0, 
     @winStreak := 0 
) v, (

    SELECT 
     player_id, 
     won, 
     timestamp, 
     @winStreak := IF(won=1,IF(@cUser=player_id,@winStreak+1,1),0) AS winStreak, 
     @cUser := player_id 
    FROM (
     (
      -- Get results where player == player_id 
      SELECT 
       player_id, 
       won, 
       timestamp 
      FROM matchTable 
     ) UNION (
      -- Get results where player == opponent_id (loss=1 is good) 
      SELECT 
       opponent_id, 
       loss, 
       timestamp 
      FROM matchtable 
     ) 
    ) m 
    ORDER BY 
     player_id ASC, 
     timestamp ASC 
) d 
GROUP BY d.player_id 

這是通過選擇全贏/輸計數的連勝。子查詢然後按player_id進行分組，並按照循環計算的最大winStreak輸出爲每個玩家。

它似乎對我的測試數據集反正很好地工作:)

要做到這一點更有效地我會重組，即

matches (
    matchID, 
    winningPlayerID, 
    timeStamp 
) 

players (
    playerID 
    -- player name etc 
) 

matchesHasPlayers (
    matchID, 
    playerID 
) 

這將導致

SELECT 
    matches.matchID, 
    matchesHasPlayers.playerID, 
    IF(matches.winningPlayerID=matchesHasPlayers.playerID,1,0) AS won 
    matches.timestamp 
FROM matches 
INNER JOIN matchesHasPlayers 
ORDER BY matches.timestamp 

內查詢

產生於

SELECT 
    d.player_id, 
    MAX(d.winStreak) AS maxWinStreak 
FROM (
    SELECT 
     @cUser := 0, 
     @winStreak := 0 
) v, (
    SELECT 
     matchesHasPlayers.playerID, 
     matches.timestamp, 
     @winStreak := IF(matches.winningPlayerID=matchesHasPlayers.playerID,IF(@cUser=matchesHasPlayers.playerID,@winStreak+1,1),0) AS winStreak, 
     @cUser := matchesHasPlayers.playerID 
    FROM matches 
    INNER JOIN matchesHasPlayers 
    ORDER BY 
     matchesHasPlayers.playerID ASC, 
     matches.timestamp ASC 
) d 
GROUP BY d.player_id 

Answer 2

SELECT * FROM 
(
    SELECT player_id, won, loss, timestamp 
    FROM games 
    WHERE player_id = 123 
    UNION 
    SELECT opponant_id as player_id, loss as won, won as loss, timestamp 
    FROM games 
    WHERE opponant_id = 123 
) 
ORDER BY timestamp 

這將會給大家一個球員的結果排序按時間戳。然後，您需要循環這些結果並計算獲勝記錄，否則將它們連接成一個字符串，然後使用字符串函數查找該字符串中最高的11111集。該代碼將根據您要使用的語言而有所不同，但從邏輯上講，這些是兩種選擇。