無法在Java的shell上運行apktool命令

Question

我試圖從Java程序中使用apktool。我正在使用它來創建Web服務。但是，該命令不能從Java程序的shell中運行。

String cmd = "apktool d /home/ridhima/Test.apk" ; 
try { 
    Process p = Runtime.getRuntime().exec(cmd); 
    BufferedReader reader = new BufferedReader(new InputStreamReader(p.getInputStream())); 
    String line = ""; 
    while((line = reader.readLine()) != null) 
    { 
     System.out.print(line + "\n"); 
    } 
    p.waitFor(); 
} 
catch (IOException | InterruptedException e1) { 
     e1.printStackTrace(); 
} 

該命令可以直接從shell中直接運行。

Answer 1

你也許應該等待的過程中，完成

String cmd = "apktool d /home/ridhima/Test.apk" ; 
try { 
    Process p = Runtime.getRuntime().exec(cmd); 
    // You maybe should wait for the process to complete 
    p.waitFor(); 
    BufferedReader reader = new BufferedReader(new InputStreamReader(p.getInputStream())); 
    String line = ""; 
    while((line = reader.readLine()) != null) 
    { 
     System.out.print(line + "\n"); 
    } 

} 
catch (IOException | InterruptedException e1) { 
     e1.printStackTrace(); 
} 

或者你可以使用的ProcessBuilder爲同一任務

public class Main { 
    public static void main(String[] args) throws java.io.IOException, java.lang.InterruptedException { 
     // Create ProcessBuilder instance for UNIX command ls -l 
     java.lang.ProcessBuilder processBuilder = new java.lang.ProcessBuilder("ls", "-l"); 
     // Create an environment (shell variables) 
     java.util.Map env = processBuilder.environment(); 
     env.clear(); 
     env.put("COLUMNS", "3"); 
     processBuilder.directory(new java.io.File("/Users")); 
     java.lang.Process p = processBuilder.start(); 
    } 
} 

Answer 2

謝謝，但現在工作得很好。由於apktool是一個包裝腳本，因此可能無法通過java程序識別。直接提取apktool.jar的作品。

try { 
     ProcessBuilder pb = new ProcessBuilder("/home/ridhima/java/jdk1.8.0/bin/java", "-jar", "apktool.jar","d","test.apk"); 
     Process p = pb.start(); 
     BufferedReader reader = new BufferedReader(new InputStreamReader(p.getInputStream())); 
     while((line = reader.readLine()) != null) { 
      System.out.print(line + "\n"); 
     } 
     p.waitFor(); 
    }catch (IOException | InterruptedException e1) { 
     e1.printStackTrace(); 
    }