所以我有一個WebView內的LinearLayout與一個EditText框和一個按鈕,使應用程序搜索網絡。當我點擊我的按鈕時,它會將我帶到股票的Android瀏覽器。如何使它在我點擊去時保持在我的WebView中? 這裏是我的佈局:WebView裏面的應用程序?
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
>
<EditText
android:id="@+id/web_address"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:text="http://"/>
<Button
android:id="@+id/go"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:background="@drawable/go"
android:gravity="right"/>
<WebView
android:id="@+id/webview"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
/>
</LinearLayout>
這裏是我的源:
package straightapp.com.Browser;
import android.app.Activity;
import android.content.Intent;
import android.net.Uri;
import android.os.Bundle;
import android.view.KeyEvent;
import android.view.View;
import android.view.View.OnClickListener;
import android.view.View.OnKeyListener;
import android.webkit.WebView;
import android.widget.Button;
import android.widget.EditText;
public class Browser extends Activity {
WebView mWebView;
Button button;
EditText text;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
mWebView = (WebView) findViewById(R.id.webview);
mWebView.getSettings().setJavaScriptEnabled(true);
mWebView.loadUrl("http://www.straightapp.com");
text=(EditText)findViewById(R.id.web_address);
button=(Button) findViewById(R.id.go);
button.setOnClickListener(new OnClickListener(){
public void onClick(View v) {
// TODO Auto-generated method stub
openBrowser();
}
});
text.setOnKeyListener(new OnKeyListener() {
public boolean onKey(View v, int keyCode, KeyEvent event) {
// TODO Auto-generated method stub
if (keyCode==KeyEvent.KEYCODE_ENTER){
openBrowser();
return true;
}
return false;
}
});
}
public void openBrowser(){
Uri uri=Uri.parse(text.getText().toString());
Intent intent=new Intent(Intent.ACTION_VIEW,uri);
startActivity(intent);
}
@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
if ((keyCode == KeyEvent.KEYCODE_BACK) && mWebView.canGoBack()) {
mWebView.goBack();
return true;
}
return super.onKeyDown(keyCode, event);
}
}
感謝
so insted:public void openBrowser(){ Uri uri = Uri.parse(text.getText()。toString()); Intent intent = new Intent(Intent.ACTION_VIEW,uri); startActivity(intent); – Christian 2011-01-29 20:46:53
我會有:公共無效openBrowser(){ Uri uri = Uri.parse(text.getText()。toString()); Intent intent = new Intent(Intent.ACTION_VIEW,uri); loadUrl(intent); – Christian 2011-01-29 20:47:30