如何用靜態方法來調用靜態類（UnitOfWork case）？

我有這些類：如何用靜態方法來調用靜態類（UnitOfWork case）？

public static class UnitOfWorkSS 
{ 
    public static IUnitOfWork Begin() 
    { 
    return IoC.Resolve<IUnitOfWork>(); 
    } 
} 

public class PostService 
{ 
    using (IUnitOfWork unitOfWork = UnitOfWorkSS.Begin()) 
    { 
    //don't forget to sanitize html content 
    htmlContent = _htmlSanitizer.Sanitize(htmlContent); 

    IPost post = _factory.CreatePost(byUser, title, htmlContent);      

    _postRepository.Add(post); 

    unitOfWork.Commit(); 
    } 
}

我怎麼能嘲笑類UnitOfWorkSS和unitOfWork？

來源

2010-11-26 Attilah

它看起來像你與呼叫做開始（）將返回您配置類特定接口的唯一的事情：IUnitOfWork

你真的只需要確保你的電話開始（）返回模擬實現的IUnitOfWork

一兩種方法可以做到這一點：

方案一 - 重構UnitOfWorkSS，使您可以設置實例將返回

public static class UnitOfWorkSS 
{ 
    private static IUnitOfWork _unitOfWork; 
    public static IUnitOfWork UnitOfWork 
    { 
     set { _unitOfWork = value; } 
     private get{ _unitOfWork ?? (_unitOfWork = IoC.Resolve<IUnitOfWork>()); } 
    } 

    public static IUnitOfWork Begin() 
    { 
     return UnitOfWork; 
    } 
} 

[TestMethod] 
public void DoStuff() 
{ 
    var mockUnitOfWork = new Mock<IUnitOfWork>(); 
    UnitOfWorkSS.UnitOfWork = mockUnitOfWork.Object; 

    //Do some setup and verify 
}

方案二 - 只要你的IoC容器註冊的IUnitOfWork一個模擬實例

private Mock<IUnitOfWork> _mockUnitOfWork; 

[TestInitialize] 
public void Init() 
{ 
    _mockUnitOfWork = new Mock<IUnitOfWork>(); 

    //Making a lot of assumptions about your IoC here... 
    IoC.Register<IUnitOfWork>(_mockUnitOfWork.Object); 
} 

[TestMethod] 
public void DoStuff() 
{ 
    _mockUnitOfWork.Setup(...); 

    //Do some verification 
}

來源

2010-11-26 04:23:40 Josh