如何檢索通過分頁的頁面中的所有選擇的選項提交表單的PHP

Question

我有很多選擇的選項，我分頁顯示每頁5選擇選項，並能正常工作像這樣

<form method="post" action="sel.php"> 
    <?php 
    --------------------------------- 
//Pagination script here 
---------------------------------------- 
//Here, I retrieve some values from database 
    $sql = "SELECT * FROM games WHERE startunix > '$nowtime' ORDER BY starttime LIMIT $offset, $rowsperpage" ; 
    $retval = mysql_query($sql); 
    while($row = mysql_fetch_array($retval, MYSQL_ASSOC)) 
    { 

//Here, I display the select option while the above values are retrived 

echo "<div align='center'><span class='style3'>{$row['home']} VS ". 
      "{$row['away']} </span></div>". 
      "<font color='#000000' size='2'>{$row['country']} | {$row['league']} | Time:{$row['starttime']} </font> <br> ". 
      "<select name='gm[$row[gamecode]|$row[starttime]|$row[home]|$row[away]]' > 
      <option value=''>Select option</option> 
    <option value='1.80 01 Both Team to Score (YES)'>1.90 Both Team to Score (YES)</option> 
    <option value='1.85 02 Both Team to Score (NO)'> 1.85 Both Team to Score (NO)</option> 
    <option value='1.90 03 Over2.5(Total Goals)'>1.90 Over2.5(Total Goals)</option> 
    <option value='1.80 04 Under 2.5(Total Goals)'>1.80 Under 2.5(Total Goals)</option> 
    <option value='1.35 05 Over 1.5 (Total Goals)'>1.35 Over 1.5 (Total Goals)</option> 
    <option value='2.60 06 Under 1.5 (Total Goals)'>2.60 Under 1.5 (Total Goals)</option> 
    <option value='2.05 07 Draw(First Half)'>2.05 Draw(First Half)</option> 
    <option value='1.55 08 Either Team Win (First Half)'>1.55 Either Team Win (First Half)</option> 
    <option value='3.70 09 Draw(Full Time)'>3.70 Draw(Full Time)</option> 
    <option value='1.20 10 Either Team Win (Full Time)'>1.20 Either Team Win (Full Time)</option> 
    <option value='1.90 11 Even(Total Goals)'>1.90 Even(Total Goals)</option> 
    <option value='1.90 12 Odd(Total Goals)'>1.90 Odd(Total Goals)</option> 
    </select>". 
      "<hr>"; 
    }//end While 
    ------------------------------ 


$range = 3; 

// if not on page 1, don't show back links 
if ($currentpage > 1) { 
    // show << link to go back to page 1 
    echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=1'>First Page |</a> "; 
    // get previous page num 
    $prevpage = $currentpage - 1; 
    // show < link to go back to 1 page 
    echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=$prevpage'>Previous Page |</a> "; 
} // end if 

// loop to show links to range of pages around current page 
for ($x = ($currentpage - $range); $x < (($currentpage + $range) + 1); $x++) { 
    // if it's a valid page number... 
    if (($x > 0) && ($x <= $totalpages)) { 
     // if we're on current page... 
     if ($x == $currentpage) { 
     // 'highlight' it but don't make a link 
     echo " [<b>$x</b>] "; 
     // if not current page... 
     } else { 
     // make it a link 
     echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=$x'>$x</a> "; 
     } // end else 
    } // end if 
} // end for 

// if not on last page, show forward and last page links   
if ($currentpage != $totalpages) { 
    // get next page 
    $nextpage = $currentpage + 1; 
    // echo forward link for next page 
    echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=$nextpage'>Next</a> "; 
    // echo forward link for lastpage 
    echo " <a href='{$_SERVER['PHP_SELF']}?currentpage=$totalpages'>| Last</a> "; 
} // end if 
----------------------------------- 



?> 
<br /><input type="submit" name="play" value="Calculate Bet" /> 
</form></div> 

這裏是後問題，如果用戶在第1頁上選擇任意數量的選項，然後單擊第2頁，並選擇第2頁上的選項，則在第3頁上選擇任何內容並繼續提交表單，只有在最後選擇頁面上選擇的選項即第2頁在表單處理頁面上檢索。我如何將所有頁面中選擇的選項值傳遞給表單處理頁面，而不僅僅是最後一頁上選擇的值？

Answer 1

有幾種方法可以通過選定的選項。

• 使用GET方法（如果在傳遞URL信息無妨）

您可以在URL中傳遞選定值例如example.com/?option=true&option2=true 並且可以檢索，即檢查選項是否使用isset（）函數 例如。 if(isset($_GET["option"])) { //do some stuffs }或if($_GET["option"]=="true") { //do some stuffs }

• 使用POST方法

有在上述方法中非常微小的差別是，得到和後一個。 您需要更改$_GET到$_POST在各情況下

其他兩種方法，你可以使用cookie和session，我不建議