簡單的JavaScript加密功能

Question

我有一個功能，必須將字符從一個數組更改爲另一個數組中的字符。這是一種簡單的加密。我有：

var plainArray = ['A','B','C',...,'Z']; 
var cipherArray = ['a','b','c',...,'z']; 
function rotateToPosition(signalCharacter, indexCharacter, plainAlphabet, cipherAlphabet) 

已經在工作。 現在我必須編寫一個函數，將給定的單詞變成加密的單詞。

function encrypt(plainText, signalCharacter, indexCharacter, plainAlphabet, cipherAlphabet) 
{ 
    var encryptedString = signalCharacter; 
    //i is what will hold the results of the encrpytion until it can be appended to encryptedString 
    var i; 
    // rotate array to signal character position 
    var rotateArray = rotateToPosition(signalCharacter, indexCharacter, plainAlphabet, cipherAlphabet); 
    for (var count = 0; count < plainText.length; count++) 
    { 
     plainAlphabet = plainText.charAt(count); 
     i = cipherAlphabet[plainAlphabet]; 
     encryptedString = encryptedString + rotateArray[i]; 
    } 

    return encryptedString; 
} 

該函數返回信號字符，然後返回一串錯誤。你知道什麼是錯的嗎？

Answer 1

您正在用一個字符覆蓋plainAlphabet，從而丟棄字母表。我想這不是你想要的。

但是，您只發布了rotateToPosition的簽名，而不是實際的代碼，所以我無法測試我的解決方案。

function encrypt(plainText, signalCharacter, indexCharacter, plainAlphabet, cipherAlphabet) { 
    var encryptedString = signalCharacter; 
    //i is what will hold the results of the encrpytion until it can be appended to encryptedString 
    var i; 
    // rotate array to signal character position 
    var rotateArray = rotateToPosition(signalCharacter, indexCharacter, plainAlphabet, cipherAlphabet); 
    for (var count = 0; count < plainText.length; count++) 
    { 
     var plainLetter = plainText.charAt(count); 
     i = cipherAlphabet[plainLetter]; 
     encryptedString = encryptedString + rotateArray[i]; 
    } 

    return encryptedString; 
}