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我正在使用LibreOffice 4.2.8，並在使用CountIf時注意到一些不一致的行爲。我想知道我是否錯過了一些東西。當我可以選擇使用正則表達式（工具 - >選項 - > LibreCalc->計算 - >在公式中啓用正則表達式）時，在包含某些控制字符的行的行上使用countif時，正則表達式。在下面的表格中將是A1，B1，C1。然而，這些相同的人物本身似乎工作得很好。在下面的表格中，A，B，C。當我轉換公式中的正則表達式時，這些差異會消失，但我注意到「=」失敗。這是一個錯誤還是我錯過了一些微妙的東西，就像在bash上逃避規則一樣？Libreoffice Calc Count如果行爲不一致
使用正則表達式開啓
A |B |C (formula in B)
------|----|---------------
One |1 |=COUNTIF(A$3:A3,A3)
Two |1 |=COUNTIF(A$3:A4,A4)
( |1 |=COUNTIF(A$3:A5,A5) <<<<<<<<<<<<< A
] |1 |=COUNTIF(A$3:A6,A6)
[ |1 |=COUNTIF(A$3:A7,A7) <<<<<<<<<<<<< B
One |2 |=COUNTIF(A$3:A8,A8)
Two |2 |=COUNTIF(A$3:A9,A9)
One (|0 |=COUNTIF(A$3:A10,A10) <<<<<<<<<<<<< A1
Two [ |0 |=COUNTIF(A$3:A11,A11) <<<<<<<<<<<<< B1
One ] |1 |=COUNTIF(A$3:A12,A12)
Two) |0 |=COUNTIF(A$3:A13,A13)
| |1 |=COUNTIF(A$3:A14,A14) <<<<<<<<<<<<< C
One | |0 |=COUNTIF(A$3:A15,A15) <<<<<<<<<<<<< C1
= |0 |=COUNTIF(A$3:A16,A16)
One = |1 |=COUNTIF(A$3:A17,A17)
+ |1 |=COUNTIF(A$3:A18,A18)
Two + |0 |=COUNTIF(A$3:A19,A19)
^ |1 |=COUNTIF(A$3:A20,A20)
& |1 |=COUNTIF(A$3:A21,A21)
* |1 |=COUNTIF(A$3:A22,A22)
One^|0 |=COUNTIF(A$3:A23,A23)
Two & |1 |=COUNTIF(A$3:A24,A24)
One * |2 |=COUNTIF(A$3:A25,A25)
使用正則表達式關閉
A |B |C (formula in B)
------|------|----------
One |1 |=COUNTIF(A$1:A1,A1)
Two |1 |=COUNTIF(A$1:A2,A2)
( |1 |=COUNTIF(A$1:A3,A3)
] |1 |=COUNTIF(A$1:A4,A4)
[ |1 |=COUNTIF(A$1:A5,A5)
One |2 |=COUNTIF(A$1:A6,A6)
Two |2 |=COUNTIF(A$1:A7,A7)
One (|1 |=COUNTIF(A$1:A8,A8)
Two [ |1 |=COUNTIF(A$1:A9,A9)
One ] |1 |=COUNTIF(A$1:A10,A10)
Two) |1 |=COUNTIF(A$1:A11,A11)
| |1 |=COUNTIF(A$1:A12,A12)
One | |1 |=COUNTIF(A$1:A13,A13)
= |0 |=COUNTIF(A$1:A14,A14) <<<<<<<<
One = |1 |=COUNTIF(A$1:A15,A15)
+ |1 |=COUNTIF(A$1:A16,A16)
Two + |1 |=COUNTIF(A$1:A17,A17)
^ |1 |=COUNTIF(A$1:A18,A18)
& |1 |=COUNTIF(A$1:A19,A19)
* |1 |=COUNTIF(A$1:A20,A20)
One^|1 |=COUNTIF(A$1:A21,A21)
Two & |1 |=COUNTIF(A$1:A22,A22)
One * |1 |=COUNTIF(A$1:A23,A23)