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我是struts 1和jQuery的新手。 我想使用AJAX請求進行登錄。 這是我的Jquery:AJAX和Struts出現問題1
$.ajax({
url : "login.do",
type: "POST",
dataType: "text",
data:{
//Got the values before
"user" : user,
"pass": pass
},
success: function(result){
if(result === "OK")
window.location = "hello.do";
}
});
我的struts-config:
<action path="/login" type="com.arquitectos.struts.LoginAction" parameter="login">
<forward name="OK" path="/"/>
</action>
我的LoginAction:
public class LoginAction extends MappingDispatchAction{
private final String error = "ERROR";
private final String success = "OK";
private final String session = "SESSION";
private Usuario user = new Usuario();
public ActionForward login(ActionMapping mapping, ActionForm form, HttpServletRequest request, HttpServletResponse response){
response.setContentType("text/texyt; charset = utf-8");
response.setHeader("Cache-Control", "no-cache");
try{
String u = request.getParameter("user");
String p = request.getParameter("pass");
if(u != null && p != null)
if(!(u.equals("")) && !(p.equals(""))){
user = TblLogin.Login(u, p);
if(user!=null)
return mapping.findForward(success);
}
}catch(Exception ex){
}
finally{
}
return mapping.findForward(null);
}
的TBL文件只是執行查詢和東西... 現在,我的疑問是:AJAX如何從前鋒獲得「OK」?如何獲取數據並在jQuery中進行比較。