2009-06-03 12 views

回答

6
function doSomething(){ console.log("Done!"); } 
var element = document.getElementById("my-element"); 
element.onClick = element.onKeyUp = element.onLoad = doSomething; 
0

我建議使用JavaScript庫的代碼從自己添加事件抽象瀏覽器差異遠。

我也建議將事件本身傳遞給函數(原型和jQuery都這樣做)。

<script> 
function doSomething(event){ 
    /*your code here*/ 
    /*this refers to the dom node in both libraries*/ 
}; 
</script> 

JQuery

<script src="http://jqueryjs.googlecode.com/files/jquery-1.3.2.js"></script> 
<script> 
    $("my-element").bind("click keyup load", doSomething); 
</script> 

Prototype

<script src="http://www.prototypejs.org/assets/2008/9/29/prototype-1.6.0.3.js"></script> 
<script> 
    $('my-element').observe('click', doSomething); 
    $('my-element').observe('keyup ', doSomething); 
    $('my-element').observe('load', doSomething); 
</script>