GraphQL：如何將參數傳遞給子對象

我正在使用GraphQL來查詢將由大約15個不同的REST調用組成的對象。這是我從查詢中傳入ID的根查詢。這適用於正確解析的主要學生對象。但是，我需要弄清楚如何將ID傳遞給地址解析器。我嘗試向地址對象添加參數，但是我得到一個錯誤，指示參數不從Student對象傳遞。所以我的問題是：我如何將客戶端查詢中的參數傳遞給GraphQL服務器中的子對象？GraphQL：如何將參數傳遞給子對象

let rootQuery = new GraphQLObjectType({ 
    name: 'Query', 
    description: `The root query`, 
    fields:() => ({ 
     Student : { 
      type: Student , 
      args: { 
       id: { 
        name: 'id', 
        type: new GraphQLNonNull(GraphQLString) 
       } 
      }, 
      resolve: (obj, args, ast) => { 
       return Resolver(args.id).Student(); 
      } 
     } 
    }) 
}); 

export default rootQuery;

這是我的主要學生對象，我鏈接其他對象。在這種情況下，我附加了ADDRESS對象。

import { 
GraphQLInt, 
GraphQLObjectType, 
GraphQLString, 
GraphQLNonNull, 
GraphQLList 
} from 'graphql'; 

import Resolver from '../../resolver.js' 
import iAddressType from './address.js' 

let Student = new GraphQLObjectType({ 
    name: 'STUDENT', 
    fields:() => ({ 
     SCHOOLCODE: { type: GraphQLString }, 
     LASTNAME: { type: GraphQLString }, 
     ACCOUNTID: { type: GraphQLInt }, 
     ALIENIDNUMBER: { type: GraphQLInt }, 
     MIDDLEINITIAL: { type: GraphQLString }, 
     DATELASTCHANGED: { type: GraphQLString }, 
     ENROLLDATE: { type: GraphQLString }, 
     FIRSTNAME: { type: GraphQLString }, 
     DRIVERSLICENSESTATE: { type: GraphQLString }, 
     ENROLLMENTSOURCE: { type: GraphQLString }, 
     ADDRESSES: { 
      type: new GraphQLList(Address), 
      resolve(obj, args, ast){ 
       return Resolver(args.id).Address(); 
     }} 
    }) 
});

這裏是由第二REST調用解決了我的地址對象：

let Address = new GraphQLObjectType({ 
    name: 'ADDRESS', 
    fields:() => ({ 
     ACTIVE: { type: GraphQLString }, 
     ADDRESS1: { type: GraphQLString }, 
     ADDRESS2: { type: GraphQLString }, 
     ADDRESS3: { type: GraphQLString }, 
     CAMPAIGN: { type: GraphQLString }, 
     CITY: { type: GraphQLString }, 
     STATE: { type: GraphQLString }, 
     STATUS: { type: GraphQLString }, 
     TIMECREATED: { type: GraphQLString }, 
     TYPE: { type: GraphQLString }, 
     ZIP: { type: GraphQLString }, 
    }) 

}); 

export default Address;

這些都是我的解析器

var Resolver = (id) => { 

    var options = { 
     hostname: "myhostname", 
     port: 4000 
    }; 


    var GetPromise = (options, id, path) => { 
     return new Promise((resolve, reject) => { 
      http.get(options, (response) => { 
       var completeResponse = ''; 
       response.on('data', (chunk) => { 
        completeResponse += chunk; 
       }); 
       response.on('end',() => { 
        parser.parseString(completeResponse, (err, result) => { 
         let pathElements = path.split('.');      
         resolve(result[pathElements[0]][pathElements[1]]); 
        }); 
       }); 
      }).on('error', (e) => { }); 
     }); 
    }; 

    let Student=() => { 
     options.path = '/Student/' + id; 
     return GetPromise(options, id, 'GetStudentResult.StudentINFO'); 
    } 

    let Address=() => { 
     options.path = '/Address/' + id + '/All'; 
     return GetPromise(options, id, 'getAddressResult.ADDRESS'); 
    }; 


    return { 
     Student, 
     Address 
    }; 
} 

export default Resolver;

來源

2016-02-25 Fallfast

FallFast：你找到任何解決方案 – Brune

你找到一個好的解決方案嗎？ – James111

ADDRESSES: { 
    type: new GraphQLList(Address), 
    resolve(obj, args, ast){ 
     return Resolver(args.id).Address(); 
    } 
}

傳遞至ADDRESSES

ARG遊戲參數傳遞給ADDRESSES字段在查詢時間。在解決方法中，obj應該是學生對象，如果您有id屬性，則只需要執行以下操作：return Resolver(obj.id).Address();。

來源

2016-07-17 18:10:45 Nish

GraphQL：如何將參數傳遞給子對象

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