我想要做的是在上傳文件後,將cvs文件解析爲print_r的屏幕,以便我可以使用它做一些事情。我似乎無法弄清楚如何使用$ data訪問文件名。我已經嘗試了幾個例如$ file_name,$ data ['file_name]和$ this-> data - > $ file_name。相關部分在線37.嘗試從上傳文件後從codeigniter獲取file_name
不知道我在做什麼錯。我已經查看了上傳器庫的代碼點火器文檔,但它不足以回答我的問題。謝謝你的幫助!
<?php
class Upload extends CI_Controller {
function __construct()
{
parent::__construct();
$this->load->helper(array('form', 'url'));
}
function index()
{
$this->load->view('upload_form', array('error' => ' '));
}
function do_upload()
{
$config['upload_path'] = './uploads/';
$config['allowed_types'] = 'csv';
$config['max_size'] = '100';
$config['max_width'] = '1024';
$config['max_height'] = '768';
$this->load->library('upload', $config);
$this->load->library('getcsv');
if (! $this->upload->do_upload())
{
$error = array('error' => $this->upload->display_errors());
$this->load->view('upload_form', $error);
}
else
{
$data = array('upload_data' => $this->upload->data());
$this->load->view('upload_success', $data);
echo 'The file name is: '.$file_name;
}
}
}
?>
會發生什麼事,當你在你面前做的var_dump($數據)加載看法? –
你可以簡單地改變這一行 - > $ data = array('upload_data'=> $ this-> upload-> data());到$ data = $ this-> upload-> data();然後訪問名稱$ data ['file_name']; – user2844810