如何檢查井字遊戲中的勝利？

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我見過如何檢查井字遊戲的勝利，但我使用的圖像，我似乎無法弄清楚如何。我想過如果使用if語句並使3個按鈕與顯示的圖像相同，但這似乎不起作用。有任何想法嗎？如何檢查井字遊戲中的勝利？

from tkinter import* 

#Window stuff 
window = Tk() 
window.title("Tic Tac Toe") 
window.configure(background = "black") 
window.geometry("400x400") 

#Variables 
global clickable 
playerXturn = True 

#Display X or O 
def buttonClicked(c) : 
    global playerXturn 
    if playerXturn == True : 
     buttonList[c]["image"] = picX 
     playerXturn = False 
     labelTurn ["text"] = "O's turn" 

    elif clickable[c] == "" : 
     buttonList[c]["image"] = picO 
     playerXturn = True 
     labelTurn ["text"] = "X's turn" 
#Check for a win 
    if button1 == picX and button2 == picX and button3 == picX: 
     print("r") 

#Images 
picX = PhotoImage (file = "x.gif") 
picO = PhotoImage (file = "o.gif") 
picBlank = PhotoImage (file = "sw.gif") 

#Buttons 
button1 = Button (window, text = "", image = picBlank, command = lambda: buttonClicked(0))  
button1.grid (row = 0, column = 0) 
#button1["state"] = DISABLED 
button2 = Button (window, text = "", image = picBlank, command = lambda: buttonClicked(1))  
button2.grid (row = 0, column = 1) 
#button2["state"] = DISABLED 
button3 = Button (window, text = "", image = picBlank, command = lambda: buttonClicked(2)) 
button3.grid (row = 0, column = 2) 
#button3["state"] = DISABLED 
button4 = Button (window, text = "", image = picBlank, command = lambda: buttonClicked(3)) 
button4.grid (row = 1, column = 0) 
#button4["state"] = DISABLED 
button5 = Button (window, text = "", image = picBlank, command = lambda: buttonClicked(4)) 
button5.grid (row = 1, column = 1) 
#button5["state"] = DISABLED 
button6 = Button (window, text = "", image = picBlank, command = lambda: buttonClicked(5)) 
button6.grid (row= 1, column = 2) 
#button6["state"] = DISABLED 
button7 = Button (window, text = "", image = picBlank, command = lambda: buttonClicked(6)) 
button7.grid (row = 2, column = 0) 
#button7["state"] = DISABLED 
button8 = Button (window, text = "", image = picBlank, command = lambda: buttonClicked(7)) 
button8.grid (row = 2, column = 1) 
#button8["state"] = DISABLED 
button9 = Button (window, text = "", image = picBlank, command = lambda: buttonClicked(8)) 
button9.grid (row = 2, column = 2) 
#button9["state"] = DISABLED 

#Labels 
labelTurn = Label (window, text = "",) 
labelTurn.grid (row = 4, column = 4) 

#Lists 
buttonList = [button1, button2, button3, button4, button5, button6, button7, button8, button9] 
clickable = ["", "", "", "", "", "", "", "", ""] 

window.mainloop()

來源

2016-01-09 Ray

的可能重複http://stackoverflow.com/questions/33178684/python-programming-3-4-2-naughts-and-crosses-best-way-對入住的how-to-看，如果-G/33179368＃33179368 – BrianO

可以使用2維列表來存儲按鈕（「X」，「O」或無）的值。之後，你應該檢查行，列和對角線。

列表例如：

table = [[0, 0, 0], 
     [0, 0, 0], 
     [0, 0, 0]]

你可以在主迴路檢查，但你也可以做到在每一次點擊處理程序檢查，以便不必要的CPU工作將被保存。

創建列表後，在檢查函數中，您可以使用像;

for row in table: 
    if set(row) == set("X"): 
     # "X"s win condition

是這樣的...

來源

2016-01-09 17:22:57 Rockybilly

如何檢查井字遊戲中的勝利？

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