2011-06-23 56 views
0

編輯 - 請忽略 - 圍繞簡單的錯字解決的問題。我需要休息。參考元素在boost.fusion向量

如何訪問提升融合矢量元素的引用?

與boost.tuples的tuples::get<i>(variable)(返回參考)不同,fusion::at_c<i>(variable)返回一個常量,這給我帶來了困難。

以下說明我的問題

#include <iostream> 
#include <boost/tuple/tuple.hpp> 
#include <boost/fusion/include/vector.hpp> 
#include <boost/fusion/include/at.hpp> 

using namespace boost; 
int 
main (int ac, char **av) 
{ 
    fusion::vector<int, char, std::string> vec(1, 'x', "howdy"); 
    tuples::tuple <int, char, std::string> tup(1, 'x', "howdy"); 
    std::cout<< fusion::at_c<0>(vec)<<std::endl; //outputs 1 
    std::cout<< tuples::get<0> (tup) <<std::endl; //outputs 1 
    //fusion::at<0>(vec) = 2; //doesn't compile 
    tuples::get<0>(tup) = 2; //works fine 
    std::cout<< fusion::at_c<0>(vec) <<std::endl; //can't make this output 2. 
    std::cout<< tuples::get<0> (tup) <<std::endl; //outputs 2 

} 

回答

1

你就不能這樣做fusion::at_c<0>(vec) = 2;

+0

doh!對不起,錯字! – Tom