在一個作業中，我得到了一個應該編寫的程序來輸出歌詞到牆上的99瓶啤酒，

Question

我似乎無法讓它在最後一節倒數。我試圖創建一個新的變量，減去1，並將該變量放在最後一節中，它適用於所有數字，但數字爲9,19,29,39 ... 99。有人可以給我一個提示或指向正確的方向嗎？我也試着創建另一個循環來倒數，並從數組中讀取它。我只有幾個月的時間才瞭解這一點，不知道還有什麼可以嘗試的。我想我曾經到了這個地步，至少對我來說，困難的一部分在我身後，並不是那麼重要。謝謝。它是Visual Studio 2010中的C++。

#include <iostream> 
#include <string> 
using namespace std; 

string tens[11] = {""," Ten"," Twenty"," Thirty"," Forty"," Fifty"," Sixty"," Seventy"," Eighty"," Ninety"}; 
string ones[10] = {"","-One","-Two","-Three","-Four","-Five","-Six","-Seven","-Eight","-Nine"}; 
string s_ones[11] = {" Zero"," One"," Two"," Three"," Four"," Five"," Six"," Seven"," Eight"," Nine"}; 
string other[ ] = {" Ten"," Eleven"," Twelve"," Thirteen"," Fourteen"," Fifteen"," Sixteen"," Seventeen"," Eighteen"," Nineteen",""}; 


int main() 
{ 
    for(int i = 99; i >= 0; --i) 
    { 
     int tens_place = i/10, ones_place = i % 10, small_ones_place = i % 10; 


     if(10 <= i && i < 20) 
     { 
      cout << other[i - 10] << " bottles of beer on the wall. \n" 
       << other[i - 10] << " bottles of beer.\n" 
       << " Take one down, pass it around,\n" 
       << other[(i - 10)] << " bottles of beer on the wall.\n\n"; 
     } 
     if(20 <= i && i <= 99) 

      cout << tens[tens_place] + ones[ones_place] << " bottles of beer on the wall. \n" 
       << tens[tens_place] + ones[ones_place] << " bottles of beer.\n" 
       << " Take one down, pass it around,\n" 
       << tens[tens_place] + ones[ones_place] << " bottles of beer on the wall.\n\n"; 

     if(2 <= i && i < 10) 

      cout << s_ones[small_ones_place] << " bottles of beer on the wall.\n" 
       << s_ones[small_ones_place] << " bottles of beer.\n" 
       << " Take one down, pass it around,\n" 
       << s_ones[small_ones_place] << " bottles of beer on the wall.\n\n"; 

     if(i == 1) 

      cout << s_ones[small_ones_place] << " bottle of beer on the wall.\n" 
       << s_ones[small_ones_place] << " bottle of beer.\n" 
       << " Take one down, pass it around,\n" 
       << s_ones[small_ones_place] << " bottles of beer on the wall.\n\n"; 

     if(i == 0) 

      cout << s_ones[small_ones_place] << " bottles of beer on the wall.\n" 
       << s_ones[small_ones_place] << " bottles of beer.\n" 
       << " Go to the store and get some more,\n" 
       << " Ninety-nine bottles of beer on the wall.\n\n"; 

     } 
return(0); 
} 

Answer 1

它非常接近正常工作。你所要做的就是在最後一行的地方索引中減去1。像這樣：

<< " Take one down, pass it around,\n" 
<< other[(i - 10)-1] << " bottles of beer on the wall.\n\n";