LINQ和xml數據

Question

我正在學習LINQ，我被困在如何去打印出部門名稱和經理姓名分開。

我有下面的代碼打印出：

Department name: Account 
       Joe 
Department name: Sales 
       Jack 
Department name: Pre-Sales 
       Sam 
Department name: Marketing 
       Jim 

我怎麼能單獨的，所以，它只會在該行打印部門名稱。

string myXML = @"<Departments> 
     <Department>Account 
     <Manager>Joe</Manager> 
     </Department> 
     <Department>Sales 
     <Manager>Jack</Manager> 
     </Department> 
     <Department>Pre-Sales 
     <Manager>Sam</Manager> 
     </Department> 
     <Department>Marketing 
     <Manager>Jim</Manager> 
     </Department> 
     </Departments>"; 

XDocument xdoc = new XDocument(); 
xdoc = XDocument.Parse(myXML); 

var DeptResult = xdoc.Element("Departments").Descendants("Department"); 
var ManagerResult = xdoc.Element("Departments").Descendants("Manager"); 

foreach (XElement item in DeptResult) 
{ 
    Console.WriteLine("Department Name - " + item.Value); 
} 

Answer 1

你可以做到這一點使用Zip擴展方法：

var departments=xdoc.Descendants("Department"); 
var managers=xdoc.Descendants("Manager"); 
foreach(var s in departments.Zip(managers, (d,m)=>"Department name: "+ 
                d.Value+"@\n"+ 
                "Manager name: "+ m.Value)) 
    Console.WriteLine(s); 

現在，就我記得的LINQ to XML返回同一順序是你的文檔中的元素和你說的存在相同數量的部門和經理，因此，您也可以重複其中一個結果並使用索引：

var departments=xdoc.Descendants("Department").ToList(); 
var managers=xdoc.Descendants("Manager").ToList(); 
for(int i=0;i<departments.Count;i++) 
{ 
    Console.WriteLine("Department Name - " + departments[i].Value); 
    Console.WriteLine("Manager Name - " + managers[i].Value); 
}