字符串中的每個字母不同的顏色，HTML PHP

我需要使用僅HTML和PHP打印不同顏色（不隨機顏色）的字符串的每個字符。它幾乎可以工作，但陣列的第一個字母是黑色的。你知道爲什麼嗎？字符串中的每個字母不同的顏色，HTML PHP

<html> 
    <?php 
     $myString = ["s","t","r","i","n","g"]; 
     $myColors = ["blue","green","yellow","brown","gray","pink"]; 

     for ($i = 0; $i < count($myString); $i++) { 
      echo "$myString[$i] <span style='color:$myColors[$i]'</span>"; 
     } 
    ?> 
</html>

來源

2017-06-06 kales

看看你的標記，其中字母內跨越....加的事實，你沒有結束'>'的跨度 –

好像你沒有正確關閉你的span標記，並且將你的字符串放入你的span中將有助於着色它。

<?php 
$myString = ["s","t","r","i","n","g"]; 
$myColors = ["blue","green","yellow","brown","gray","pink"]; 

for ($i = 0; $i < count($myString); $i++) { 
    echo "<span style='color:$myColors[$i]'>$myString[$i]</span>"; 
}

來源

2017-06-06 15:37:59 reinierkors

的字符不是彩色跨度內，你缺少一個>：

echo "<span style='color:$myColors[$i]'>$myString[$i]</span>";

來源

2017-06-06 15:38:04 Halcyon

我覺得你的HTML被打破了。您需要在<span>元素內包含$myString[$i]並正確關閉它。

$myString = ["s","t","r","i","n","g"]; 
$myColors = ["blue","green","yellow","brown","gray","pink"]; 

for ($i = 0; $i < count($myString); $i++) { 
    echo "<span style='color:$myColors[$i]'>$myString[$i]</span>"; 
}

來源

2017-06-06 15:38:05

<html> 
<?php 
$myString = ["s","t","r","i","n","g"]; 
$myColors = ["blue","green","yellow","brown","gray","pink"]; 

for ($i = 0; $i < count($myString); $i++) { 

    echo "<span style='color:$myColors[$i]'> $myString[$i] </span>"; 

} 
?> 
</html>

來源

2017-06-06 15:54:19

字符串中的每個字母不同的顏色，HTML PHP

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