JSON對象內部而不是陣列中的多個JSON對象

Question

我正在使用提供以下響應的API。 （爲簡單起見，我已將數據內的對象數量減少到2個）。

{ 
"Response": "Success", 
"Message": "Coin list succesfully returned!", 
"BaseImageUrl": "https://www.cryptocompare.com", 
"BaseLinkUrl": "https://www.cryptocompare.com", 
"Data": { 
      "42": { 
      "Id": "4321", 
      "Url": "/coins/42/overview", 
      "ImageUrl": "/media/19984/42.png", 
      "Name": "42", 
      "CoinName": "42 Coin", 
      "FullName": "42 Coin (42)", 
      "Algorithm": "Scrypt", 
      "ProofType": "PoW", 
      "FullyPremined": "0", 
      "TotalCoinSupply": "42", 
      "PreMinedValue": "N/A", 
      "TotalCoinsFreeFloat": "N/A", 
      "SortOrder": "34" 
      }, 
      "365": { 
      "Id": "33639", 
      "Url": "/coins/365/overview", 
      "ImageUrl": "/media/352070/365.png", 
      "Name": "365", 
      "CoinName": "365Coin", 
      "FullName": "365Coin (365)", 
      "Algorithm": "X11", 
      "ProofType": "PoW/PoS", 
      "FullyPremined": "0", 
      "TotalCoinSupply": "2300000000", 
      "PreMinedValue": "N/A", 
      "TotalCoinsFreeFloat": "N/A", 
      "SortOrder": "916" 
      } 
}, 
"Type": 100 
} 

我想將所有對象放在數據中的數組中，以便我可以將它們傳遞給我的RecyclerView的適配器。

我利用Retrofit2和RxJava2進行網絡操作。

這是我改裝製造商此刻的代碼：http://www.jsonschema2pojo.org/

我已編輯類數據，以便它包含：

Retrofit retrofit = new Retrofit.Builder() 
        .baseUrl(BASE_URL) 
        .client(client) 
        .addConverterFactory(GsonConverterFactory.create()) 
        .addCallAdapterFactory(RxJava2CallAdapterFactory.create()) 
        .build(); 

我使用也產生了POJO類硬幣和數據數組硬幣而不是單個對象：

public class Data { 
@SerializedName("Coin") 
    @Expose 
    private Coin[] coins; 

    public Coin[] getCoin() { 
     return coins; 
    } 

    public void setCoins(Coin[] coins){} 
} 

我會如何去添加數據中的所有對象到Coin數組？ 我是否需要創建自定義轉換器，如果是，我該如何實現？

在此先感謝！

Answer 1

這是你的數據類：

import com.google.gson.Gson; 
import com.google.gson.TypeAdapter; 
import com.google.gson.annotations.JsonAdapter; 
import com.google.gson.stream.JsonReader; 
import com.google.gson.stream.JsonWriter; 

import java.io.IOException; 
import java.util.ArrayList; 


@JsonAdapter(Data.DataJsonAdapter.class) 
public class Data { 
    private Coin[] coins; 

    public Coin[] getCoin() { 
     return coins; 
    } 

    public void setCoins(Coin[] coins) { 
     this.coins = coins; 
    } 

    public static class DataJsonAdapter extends TypeAdapter<Data> { 
     @Override 
     public void write(JsonWriter out, Data value) throws IOException { 
      // TODO: Maybe implement 
     } 

     @Override 
     public Data read(JsonReader reader) throws IOException { 
      ArrayList<Coin> coins = new ArrayList<>(); 
      Gson gson = new Gson(); 
      reader.beginObject(); 
      while (reader.hasNext()) { 
       reader.nextName(); // Read "42", "365", ... 
       coins.add(gson.fromJson(reader, Coin.class)); 
      } 
      reader.endObject(); 

      Data data = new Data(); 
      // Can probably be simplified 
      Coin[] array = new Coin[coins.size()]; 
      coins.toArray(array); // fill the array 
      data.setCoins(array); 

      return data; 
     } 
    } 
} 

然後在某處你的代碼，只要致電：

Gson gson = new Gson(); 
Data data = gson.fromJson(yourJson, Data.class); 

我沒有，但你應該檢查是否有下一個在閱讀閱讀器時預期的類型，以防止崩潰。

Answer 2

public class All_Plan { 

    @SerializedName("Coin") 
    private ArrayList<CoinData> data; 

    @SerializedName("status") 
    private String status; 

    public ArrayList<CoinData> getData() { 
     return data; 
    } 

    public void setData(ArrayList<CoinData> data) { 
     this.data = data; 
    } 

    public String getStatus() { 
     return status; 
    } 

    public void setStatus(String status) { 
     this.status = status; 
    } 
}