2017-07-19 34 views
0

這是捲曲。創建與Curl命令相同的RestSharp

curl -H "Content-Type: application/json" -vX POST -d "[\"Channel1.Device1.tag1\"]" host_name/read 

我需要將其轉換成restSharp代碼,

目前,我做的,

var client = new RestClient("host_name/read"); 

var request = new RestRequest(Method.POST); 

IRestResponse response = client.Execute(request); 
var content = response.Content; // raw content as string 

我不知道如何解決這個-d PARAM。

回答