如何在吐司中顯示數組列表項？

Question

我使用JSON解析，我並且發送5個電子郵件和五個名字，並響應它給

{ 
    "invitefriend": [ 
     { 

      "message": "Friend Request sent to : abc" 
     }, 
     { 

      "message": "Friend Request sent to : def" 
     } 
    ] 
} 

現在我想做是我想在敬酒ABC和閃避，但它提供了一個接一個分開

JSONArray jsonary=json.getJSONArray("invitefriend"); 

      for (int i = 0; i < jsonary.length(); i++) { 
       JSONObject c = jsonary.getJSONObject(i); 
       // creating new HashMap 
       HashMap<String, String> map = new HashMap<String, String>(); 
       // adding each child node to HashMap key => value 
       // map.put(INTERESTACCEPT_USER_ID, c.getString(INTERESTACCEPT_USER_ID)); 
       map.put(TAG_SUCCESS_INVITE,c.getString(TAG_SUCCESS_INVITE)); 
       map.put(TAG_SUCCESS_MESSAGE, c.getString(TAG_SUCCESS_MESSAGE)); 

       ArrayList<String> msgs=new ArrayList<String>(); 
       msgs=map.put(TAG_SUCCESS_MESSAGE, c.getString(TAG_SUCCESS_MESSAGE)); 
       System.out.println("MESSAGE : " + msg); 

       // adding HashList to ArrayList 

       getActivity().runOnUiThread(new Runnable() { 
        @Override 
        public void run() { 
         Toast.makeText(getActivity(),""+msgs, Toast.LENGTH_LONG).show(); 
        } 
       }); 
       data.add(map); 
      } 

Answer 1

你越來越多Toast因爲你是Toast荷蘭國際集團的for循環中。簡單地說就是呼叫轉移到外循環：

JSONArray jsonary=json.getJSONArray("invitefriend"); 
ArrayList<String> msgs=new ArrayList<String>(); 
String msg = null; 

for (int i = 0; i < jsonary.length(); i++) { 
    JSONObject c = jsonary.getJSONObject(i); 
    // creating new HashMap 
    HashMap<String, String> map = new HashMap<String, String>(); 
    // adding each child node to HashMap key => value 
    // map.put(INTERESTACCEPT_USER_ID, c.getString(INTERESTACCEPT_USER_ID)); 
    map.put(TAG_SUCCESS_INVITE,c.getString(TAG_SUCCESS_INVITE)); 
    map.put(TAG_SUCCESS_MESSAGE, c.getString(TAG_SUCCESS_MESSAGE)); 

    msg=map.put(TAG_SUCCESS_MESSAGE, c.getString(TAG_SUCCESS_MESSAGE)); 
    msgs.add(msg); 
    System.out.println("MESSAGE : " + msg); 

    // adding HashList to ArrayList 
    data.add(map); 
} 

getActivity().runOnUiThread(new Runnable() { 
     @Override 
     public void run() { 
      Toast.makeText(getActivity(), msgs.toString(), Toast.LENGTH_LONG).show(); 
     } 
    }); 

此外，我們已經定義了ArrayListmsgs收集響應消息，我們Toast直接與msgs.toString()。

Answer 2

你必須做「」+數組列表然後它會顯示烤麪包中的所有數組列表項。或者，如果你需要一個都是一個，然後拿一個for循環與數組列表的長度在你剛剛添加的數組列表[i]像

for (int i=0;i<=arraylist.length;i++){ 

     Toast.makeText(getContext(),arraylist[i],Toast.LENGTH_SHORT).show(); 
    } 

Answer 3

嘗試這樣的。我認爲它有幫助

featured_list = new ArrayList<Featured>(); 
for (int i = 0; i < jarray.length(); i++) { 
JSONObject object = jarray.getJSONObject(i); 
Toast.makeText(getApplicationContext(), object.getString("thumb").toString(), Toast.LENGTH_LONG).show(); 
}    

Answer 4

試試這個，

JSONArray jsonary=json.getJSONArray("invitefriend"); 
    ArrayList<String> msgs; 
      for (int i = 0; i < jsonary.length(); i++) { 
       JSONObject c = jsonary.getJSONObject(i); 
       // creating new HashMap 
       HashMap<String, String> map = new HashMap<String, String>(); 
       // adding each child node to HashMap key => value 
       // map.put(INTERESTACCEPT_USER_ID, c.getString(INTERESTACCEPT_USER_ID)); 
       map.put(TAG_SUCCESS_INVITE,c.getString(TAG_SUCCESS_INVITE)); 
       map.put(TAG_SUCCESS_MESSAGE, c.getString(TAG_SUCCESS_MESSAGE)); 

       msgs = new ArrayList<String>(map.values()); 

       System.out.println("MESSAGE : " + msgs); 

       // adding HashList to ArrayList 


       data.add(map); 
      } 
      getActivity().runOnUiThread(new Runnable() { 
        @Override 
        public void run() { 
         Toast.makeText(getActivity(),msgs,Toast.LENGTH_LONG).show(); 
        } 
       });