內的另一個列表蟒蛇

Question

拆包列表假設你有一個清單：

mylist=[[1,2,3,4],[2,3,4,5],[3,4,5,6]] 

任何Python化（2.X）的方式來解壓內部列表，這樣新的名單應該是這樣的：？

mylist_n=[1,2,3,4,2,3,4,5,3,4,5,6] 

Answer 1

import itertools 
mylist=[[1,2,3,4],[2,3,4,5],[3,4,5,6]] 
print list(itertools.chain(*mylist)) 

Answer 2

mylist_n = [j for i in mylist for j in i]