2013-11-03 57 views
0

我試圖從一個目錄中加載.JPEG圖像,並通過點擊按鈕將其加載到ListBox,這是我實現的目標。但是,我需要將這些圖像放入PictureBox。有人能指點我正確的方向嗎?這是我迄今爲止。將圖像從列表框加載到圖片框

public partial class Form1 : Form 
{ 
    public Form1() 
    { 
     InitializeComponent(); 
    } 

    private void listBox1_SelectedIndexChanged(object sender, EventArgs e) 
    { 
     DirectoryInfo dinfo = new DirectoryInfo(@"C:\cake"); 

     FileInfo[] Files = dinfo.GetFiles(); 

     foreach (FileInfo file in Files) 
     { 
      listBox1.Items.Add(file.Name); 
     } 
    } 

    private void button1_Click(object sender, EventArgs e) 
    { 
     listBox1.Items.Add(@"C:\cake"); 
    } 

    private void pictureBox1_Click(object sender, EventArgs e) 
    { 
     string[] x = System.IO.Directory.GetFiles(@"C:\cake", "*.jpeg"); 
     pictureBox1.SizeMode = PictureBoxSizeMode.StretchImage; 

     for (int i = 0; i < x.Length; i++) 
     { 
      listBox1.Items.Add(x[i]); 
     } 
    } 
} 

回答

0

應該看起來更像...

private void button1_Click(object sender, EventArgs e) 
    { 
     listBox1.Items.Clear(); 
     DirectoryInfo dinfo = new DirectoryInfo(@"C:\cake"); 
     FileInfo[] Files = dinfo.GetFiles("*.jpeg"); 
     listBox1.Items.AddRange(Files); 
     listBox1.DisplayMember = "FileName"; 
    } 

    private void listBox1_SelectedIndexChanged(object sender, EventArgs e) 
    { 
     if (listBox1.SelectedIndex != -1) 
     { 
      FileInfo fi = (FileInfo)listBox1.SelectedItem; 
      pictureBox1.ImageLocation = fi.FullName; 
     } 
    } 
0

這應該是你正在尋找的是如何使用圖像位置在圖片框中顯示圖像。

pictureBox1.ImageLocation("Image Location"); 

如果你想要用戶能夠選擇圖像嘗試這樣的事情。

 OpenFileDialog dlg = new OpenFileDialog(); 
     dlg.Filter = "JPEG FILES(*.jpeg)"; 
     if (dlg.ShowDialog() == DialogResult.OK) 
     { 
      pictureBox1.ImageLocation(dlg.FileName.ToString()); 
     } 
+0

由於生病嘗試! – bagel123

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