讀返回對象在JQuery中

Question

讀返回對象在JQuery中 4分鐘前| LINK

我創建了一個WCF服務，返回GenericList對象。我需要閱讀使用jQuery在客戶端該對象，但可以得到它的工作：

下面

是我的代碼：

SVC方法：

[OperationContract] 
    [WebGet(ResponseFormat = WebMessageFormat.Json)] 
    public CommentList GetComments() 
    { 
     Comments oComment1 = new Comments(); 
     oComment1.Title = "AMaking hay when the sun shines"; 
     oComment1.Author = "Plan_A"; 
     oComment1.CommentText = "AI like hay almost as much as I like sun. Just joking"; 

     Comments oComment2 = new Comments(); 
     oComment2.Title = "Making hay when the sun shines"; 
     oComment2.Author = "Plan_B"; 
     oComment2.CommentText = "I like hay almost as much as I like sun. Just joking"; 

     CommentList oCommentList = new CommentList(); 
     oCommentList.Comment.Add(oComment1); 
     oCommentList.Comment.Add(oComment2); 

     return oCommentList; 
    } 

在客戶端

jQuery腳本：

$('#CommentsButton').click(function() { 
     $.getJSON('http://localhost:55679/RESTService.svc/GetComments?callback=?', function (data) { 
       alert(data); 

     }); 

響應我越來越（通過Inspect元素 - 鉻工具）

jsonp1363710839478({"Comment":[{"Author":"Plan_A","CommentText":"AI like hay almost as much as I like sun. Just joking","Title":"AMaking hay when the sun shines"},{"Author":"Plan_B","CommentText":"I like hay almost as much as I like sun. Just joking","Title":"Making hay when the sun shines"}]}); 

Answer 1

試試這個：

$.getJSON('http://localhost:55679/RESTService.svc/GetComments?callback=?', function (data) { 
    alert(data.Comments[0].Author); 
}); 

Answer 2

這工作。

$.ajax({ 
     type : "GET", 
     dataType : "jsonp", 
     url : 'http://localhost:55679/RESTService.svc/GetComments', 
     success: function(data){ 
      console.log(data.Comment.length); 
      for(var i=0; i<data.Comment.length; i++){ 
       console.log(data.Comment[i].Title); 
      } 
     } 
    });