PHP - 解析錯誤：語法錯誤，意想不到的T_IF

Question

解析錯誤：語法錯誤，意想不到的「如果」（T_IF）在StatusIG.php在線25

我真的不看在我的代碼的任何問題，這是爲什麼發生，請幫助。在PHP IM初學者

我的第25行是>>如果（$狀態== 0）

 

    $accountdb_ip = "ip"; //Accountserver-IP 
    $accountdb_login = "acc"; //Accountserver-Loginname 
    $accountdb_pw = "psw"; //Accountserver-Passwort 
    $db_ip = "ip"; //DB-Server-IP 
    $db_login = "acc"; //DB-Server-Loginname 
    $db_pw = "psw"; //DB-Server-Passwort 

    $con = mysql_connect($db_ip, $db_login, $db_pw); 
    $con_account = mysql_connect($accountdb_ip, $accountdb_login, $accountdb_pw); 
    if (!$con) 
     { 
     die('Could not connect: ' . mysql_error()); 
     } 

    $name = mysql_real_escape_string($_GET["name"], $con); 

    $result_id = mysql_query("SELECT * FROM player.player WHERE name='".$name."' LIMIT 1", $con); 
    $player_acc_id = mysql_result($result_id, 0, "account_id"); 

    $result = mysql_query("SELECT * FROM account.account WHERE id='".$player_acc_id."'", $con); 
    $status = mysql_result($result, 0, "raiguard") 

    if($status == 0) 
     {echo "0";} 
    elseif($status == 1) 
     {echo "1";} 
    elseif($status == 2) 
     {echo "2";} 

    mysql_close($con); 
    mysql_close($con_account); 

Answer 1

你錯過了結束分號：

$status = mysql_result($result, 0, "raiguard") 

將其替換爲：

$status = mysql_result($result, 0, "raiguard");