用引號輸出數組的問題

Question

我一直在試圖讓下面的代碼返回一個內部的兩個一等數組..例如：[ 'July 1st', '4th' ]。但是，到目前爲止，我的代碼返回：[ 'July 1st, 4th' ]。請注意，我需要它有確切的引號。

這是我的代碼：

function friendly(str) { 
    var final = []; 
    var months = {01:"January" , 02: "February", 03:"March", 04:"April", 05:"May", 06:"June", 07:"July", 08:"August", 09:"September", 10:"October", 11:"November", 12:"December"}, i, c, date1, date2, getYear1, getMonth1, getDay1, getYear2, getMonth2, getDay2; 
    var days = {01: "st", 02: "nd", 03: "rd", 04: "th", 05: "th"}; 
    date1 = str[0]; 
    date1.split('-'); 
    date2 = str[1]; 
    date2.split('-'); 
    getYear1 = date1.substring(0, 4); 
    getMonth1 = date1.substring(5, 7); 
    getMonth2 = date2.substring(5, 7); 
    getDay1 = date1.substring(8, 10); 
    getYear2 = date2.substring(0,4); 
    getMonth2 = date2.substring(5,7); 
    getDay2 = date2.substring(8, 10); 
    for(var key in months){ 
    //console.log(getMonth1.charAt(0) == 0); 
    if(getMonth1.charAt(0) == 0){ 
     getMonth1 = getMonth1.slice(1); 
    } 
    if(getMonth2.charAt(0) == 0){ 
     getMonth2 = getMonth2.slice(1); 
    } 
    if(getDay1.charAt(0) == 0){ 
     getDay1 = getDay1.slice(1); 
    } 
    if(getDay2.charAt(0) == 0){ 
     getDay2 = getDay2.slice(1); 
    } 
    if(days.hasOwnProperty(getDay1)){ 
     getDay1 = getDay1 + days[getDay1]; 
    } 
    if(days.hasOwnProperty(getDay2)){ 
     getDay2 = getDay2 + days[getDay2]; 
    } 
    if(months.hasOwnProperty(getMonth1)){ 
     getMonth1 = months[getMonth1]; 
    } 
    if(months.hasOwnProperty(getMonth2)){ 
     getMonth2 = months[getMonth2]; 
    } 
    if(getMonth1 == getMonth2 && getYear1 == getYear2 && getDay1 !== getDay2){ 
     return [getMonth1 + ' ' + getDay1 + ', ' + getDay2.split(',')]; 
     //console.log(getMonth1); 
    } 
    else if(getMonth1 == getMonth2 && getYear1 == getYear2 && getDay1 == getDay2){ 
    return [getMonth1 + ' ' + getDay1 + ', ' + getYear1]; 
    } 
    else if(getYear1 !== getYear2 && getMonth1 !== getMonth2 && getDay1 !== getDay2){ 
    return [getMonth1 + ' ' + getDay1 + ', ' + getMonth2 + ' '+ getDay2.split(',')]; 
    } 
    else if(getYear1 == getYear2 && getMonth1 !== getMonth2 && getDay1 !== getDay2){ 
     return [getMonth1 + ' ' + getDay1 + ', ' + getMonth2 + ' '+ getDay2 + ', ' + getYear1]; 
    } 
    else if(getYear1 == getYear2 && getMonth1 !== getMonth2 && getDay1 !== getDay2){ 
     return; 
    } 
    else if (getYear1 !== getYear2 && getMonth1 == getMonth2 && getDay1 !== getDay2){ 
    return [getDay1 + ', ' + getDay2.split(',')]; 
    } 
    } 

} 

friendly(['2015-07-01', '2015-07-04']); 

Answer 1

你正在構建一個字符串並與數組文本加以包裝。

從你所描述的，它看起來像你想建立一個數組多個項目，這是你的變量。

例如

[getMonth1 + ' ' + getDay1 + ', ' + getDay2.split(',')]; 
//      ^^^^^^^^^^  ^^^^^^^^^^^^^ 
// becomes 
[getMonth1 + ' ' + getDay1, getDay2]; 
//      ^^  ^
// or possibly 
[getMonth1 + ' ' + getDay1].concat(getDay2.split(',')); 

---

您已經發布了大量的代碼，很少真正屬於您的問題，當你試圖在未來的調試考慮您的變量每行什麼，然後你應該能夠將問題解決或縮小爲一個簡單的例子，這對每個人都會更容易理解，例如

var foo = "July", // it doesn't matter how we arrived at these variables 
    bar = "1st", // all that will matter for the question is how they 
    baz = "4th"; // are used from here onwards 
[foo + ' ' + bar + ', ' + baz]; // unexpected result 
[foo + ' ' + bar, baz];   // expected result 

Answer 2

還有很多方法可以讓代碼少得多。這裏有一個很好的啓發你！

function friendly(arrDates) { 
    var suffixes = ["", "st", "nd", "rd"]; 
    var months = ["", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]; 
    var result = []; 
    arrDates.forEach(function(date) { 
     var parts = date.split("-"); 
     result.push(
      months[parseInt(parts[1])] + 
      " " + 
      (parts[2].slice(0,1) == 0 ? parts[2].slice(1) : parts[2]) + 
      (suffixes[parseInt(parts[2])] || "th") 
     ); 
    }); 
    return result; 
} 
result = friendly(['2015-07-01', '2015-07-04', '2015-09-16']); 
console.log(result); 

這種打印出：

[ 'July 1st', 'July 4th', 'September 16th' ] 

EG - http://repl.it/xip

使用forEach像這意味着您可以提供任意數量的日期 - 我的演示展示了3