在java中使用正則表達式分隔自定義標籤的內容

Question

我需要一段代碼來抓取Java中的一個String中的標籤所包圍的所有值，並將它們作爲字符串數組返回，如果標籤名稱與一系列關鍵字匹配的話。這些標籤都是由「<>」包圍的普通文本字，以及爲所創建的每個標籤都包圍「」的結束標籤。

Ex。在文本的

<name>stuff<name/> 
    <locations>example of text<locations/> 
    <storybattles>more text somehow<storybattles/> 
    <maincharacter>characters n stuff <maincharacter/> 
//continues on with random tag text values 

returns-

"stuff" 
"example of text" 
"more text somehow" 
"characters n stuff" 

最好用的閱讀病例

String inputText="pretend there are tags in here"; 
//Please pretend I added several keywordsd to the keywords list 
ArrayList<String> keywords=new ArrayList<String>(); 
String[] allTheAnswers=kindStackOverflowMentorMethod(inputText,keywords); 

雖然我可以用我有限的正則表達式的知識，這樣做我自己，我只是畏縮因爲我知道這可以做得更好。如果你包含對你使用的正則表達式的每個部分的解釋（或者一個聰明的頭腦可能會做的任何解決方案），那麼你從我那裏得到額外的分數。

Answer 1

這裏是我會怎麼做工作的例子：

private static final String DATA = "<name>stuff<name/>\n" + 
     " <locations>example of text<locations/>\n" + 
     " <storybattles>more text somehow<storybattles/>\n" + 
     " <maincharacter>characters n stuff <maincharacter/>"; 

private static final List<String> KEYWORDS = Arrays.asList(
     new String[]{"name", "locations"}); 

private static final String PATTERN = "<%1$s>(.+?)<%1$s/>"; 

public static void main(String[] args) { 

    List<String> strs = new ArrayList<>(); 
    for (String keyword : KEYWORDS) { 
     String tempPattern = String.format(PATTERN, keyword); 
     Pattern pattern = Pattern.compile(tempPattern); 
     Matcher matcher = pattern.matcher(DATA); 

     while(matcher.find()){ 
      strs.add(matcher.group(1)); 
     } 
    } 
} 

Regex101 Fiddle

Answer 2

你在找這個？

import java.util.ArrayList; 
import java.util.regex.Matcher; 
import java.util.regex.Pattern; 


public static void main(String[] args) { 

    String inputText=" <name>stuff<name/>\n"+ 
     " <locations>example of text<locations/>\n"+ 
     " <storybattles>more text somehow<storybattles/>\n"+ 
     " <maincharacter>characters n stuff <maincharacter/>"; 

    //Please pretend I added several keywordsd to the keywords list 
    ArrayList<String> keywords=new ArrayList<>(); 
    keywords.add("locations"); 
    keywords.add("maincharacter"); 

    //Call the function 
    ArrayList<String> allTheAnswers=kindStackOverflowMentorMethod(inputText,keywords); 

} 

public static ArrayList<String> kindStackOverflowMentorMethod(String inputText, ArrayList<String> keywords){ 
    ArrayList<String> values=new ArrayList<>(); 
    Matcher m = Pattern.compile("<([a-z][a-z0-9]*)>(.*?)<(?:\\1)\\/>").matcher(inputText); 
    while (m.find()){ 
     if (keywords.indexOf(m.group(1)) > -1) { 
      values.add(m.group(2));    
     } 
    } 
    return values; 
} 

正則表達式的說明

<     # match < literally 
([a-z][a-z0-9]*) # first capturing group - match TAG name 
         should start with a letter, followed by 
         0 or more letters or numbers 
>     # match > literally 
(.*?)    # 2nd capturing group - match content surrounded by TAGs 
         non-greedy match 
<     # match < literally 
(?:\1)    # non-capturing group - match previous matched TAG name 
\/>     # match /> literally