從目標C發送變量到php Cocoa

Question

我想將一個變量傳遞給一個php頁面，但它沒有被傳遞到頁面或被保存在數據庫中。請參閱以下代碼中的註釋：

NSString *fname=@"fname"; 
NSString *lname=@"lname"; 
NSString *urlString = [[NSString alloc] initWithFormat:@"http://localhost:8888/Test-objective%20c%20/send.php?first_name=%@&last_name=%@",fname,lname]; 

NSLog(urlString); 

NSURL *url = [ NSURL URLWithString:urlString]; 
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url]; 
NSAlert *dq= [[NSAlert alloc] init]; 
[dq setMessageText:urlString]; 
[dq runModal]; 
[request setHTTPMethod:@"GET"]; 

NSURLConnection* connection = [[NSURLConnection alloc] initWithRequest:request delegate:self]; 
[connection start]; 

NSAlert *d= [[NSAlert alloc] init]; 
[d setMessageText:@"connection"]; 
[d runModal]; 

//This is the part I don't understand. 
//This line has a problem: 
NSString *urlString = [[NSString alloc] initWithFormat:@"http://localhost:8888/Test-objectivec/send.php?first_name=%@&last_name=%@",fname,lname]; 

//But when I replace it with 
NSString *urlString = @"http://localhost:8888/Test-objectivec/send.php?first_name=My&last_name=nme"; 

//Then it works just fine. 

此外，任何人都可以告訴我如何看到服務器的響應？

Answer 1

NSString *fname=@"fname"; 
NSString *lname=@"lname"; 
NSString *urlString = [[NSString alloc] 

NSString *urlString = [[NSString alloc]initWithFormat:@"http://localhost:8888/Test-objectivec/send.php?first_name=%@&last_name=%@",fnamelname]; 

• 從「測試目標C」，其轉化％20這一情況問題去掉空白。

Answer 2

當您使用格式創建字符串時，您需要注意格式中的特殊字符。特別是在你的情況下%。格式應該是：

NSString *urlString = [[NSString alloc] initWithFormat:@"http://localhost:8888/Test-objective%%20c%%20/send.php?first_name=%@&last_name=%@",fname,lname];