PHP重載，單例實例

Question

我已經創建了自己的MVC框架，並且很好奇其他框架如何將屬性從「控制器」發送到「視圖」。 Zend公司確實沿$this->view->name = 'value';我的代碼行的東西是：

文件：services_hosting.php

class services_hosting extends controller { 
    function __construct($sMvcName) { 
     parent::__construct($sMvcName); 

     $this->setViewSettings(); 
    } 

    public function setViewSettings() {   
     $p = new property; 
     $p->banner = '/path/to/banners/home.jpg'; 
    } 
} 

文件：Controller.php這樣

class controller { 
    public $sMvcName = "home"; 

    function __construct($sMvcName) { 
     if ($sMvcName) { 
      $this->sMvcName = $sMvcName; 
     } 

     include('path/to/views/view.phtml'); 
    } 

    public function renderContent() { 
     include('path/to/views/'.$this->sMvcName.'.phtml'); 
    } 
} 

文件：property.php

class property { 

    private $data = array(); 
    protected static $_instance = null; 

    public static function getInstance() { 
     if (null === self::$_instance) { 
      self::$_instance = new self(); 
     } 

     return self::$_instance; 
    } 

    public function __set($name, $value) { 
     $this->data[$name] = $value; 
    } 

    public function __get($name) { 
     if (array_key_exists($name, $this->data)) { 
      return $this->data[$name]; 
     } 
    } 

    public function __isset($name) { 
     return isset($this->data[$name]); 
    } 

    public function __unset($name) { 
     unset($this->data[$name]); 
    } 

} 

在我的services_hosting.phtml「查看」文件中，我有：

<img src="<?php echo $this->p->banner ?>" /> 

這只是行不通的。我在做一些根本性的錯誤，或者我的邏輯不正確？目前我似乎正在圈圈。任何幫助將非常感激。

Answer 1

我的前端控制器看起來像這

class front { 

    private $sMvcName = 'home'; 

    function __construct() { 
     $aUriParts = $this->getUriParts(); 

     if ($aUriParts[0]) { 
      $this->sMvcName = implode("_", $aUriParts); 
     } 

     $this->constructController(); 
    } 

    private function constructController() { 
     $this->view = new property(); 
     $sControllerName = $this->sMvcName; 
     new $sControllerName($this->sMvcName); 
    } 

    private function getUriParts() { 
     $sUri = $_SERVER['REQUEST_URI']; 
     $sUri = trim($sUri, "/"); 
     $sUri = str_replace("-", "_", $sUri); 
     $aUriParts = explode("/", $sUri); 
     return $aUriParts; 
    } 

} 

services_hosting.php現在看起來像這樣

class services_hosting extends controller { 

    function __construct($sMvcName) { 
     $this->setViewSettings(); 

     parent::__construct($sMvcName); 
    } 

    public function setViewSettings() { 
     $this->view->banner = '/assets/images/banners/home_02.jpg'; 
    } 

} 

Answer 2

你可以檢查它是否有效嗎？

在你Controller.php這樣您在我們的服務託管控制器

class services_hosting extends controller { 
function __construct($sMvcName) { 
    parent::__construct($sMvcName); 

$this->view->banner = '/path/to/banners/home.jpg'; 
} 

}

旗幟變量應該是在你的視圖文件訪問現在創建視圖對象

function __construct() { 
    $this->view = new property(); 
} 

現在。

<img src="<?php echo $this->banner ?>" /> 

希望這將工作...

Answer 3

<img src="<?php echo $this->p->banner ?>" /> 

implys你在一個類的實例。你說其外部文件，所以你將有可能沿

$a = new services_hosting(); 

線的東西在這種情況下，而不是

$this->banner; 

你會

$a->banner;