基於多個屬性根據優先級排序javascript對象

我有一個對象，我使用的是ng-repeat，但需要顯示可排序的合成項中的項目如果多個項目的總值與排序的總值相同，應對總值進行排序應該根據p1的值來完成，如果p1與p2相同，並且如果p2也相同，那麼p3.i已經基於總值排序了對象，但是仍然優先考慮如何基於多個對象屬性進行排序？基於多個屬性根據優先級排序javascript對象

我已經做了基礎的價值和重點排序上，但需要幫助的這種複雜的情況

{ "QVC":{ 
      "p1":0, 
      "p2":12, 
      "p3":12, 
      "total":24, 
      "org":"QVC" 
     }, 
     "TURNER & TOWNSEND":{ 
      "p1":12, 
      "p2":12, 
      "p3":0, 
      "total":24, 
      "org":"TURNER & TOWNSEND" 
     }, 
     "EDF ENERGY":{ 
      "p1":12, 
      "p2":0, 
      "p3":12, 
      "total":24, 
      "org":"EDF ENERGY" 
     }, 
     "TOWERS WATSON":{ 
      "p1":6, 
      "p2":0, 
      "p3":6, 
      "total":12, 
      "org":"TOWERS WATSON" 
     }, 
     "VODAFONE UK LTD":{ 
      "p1":0, 
      "p2":1, 
      "p3":0, 
      "total":1, 
      "org":"VODAFONE UK LTD" 
     }, 
     "DENPLAN LTD":{ 
      "p1":1, 
      "p2":0, 
      "p3":0, 
      "total":1, 
      "org":"DENPLAN LTD" 
     } 

    }

來源

2016-06-01 Shailendra Sharma

請發表評論，如果你要投票做 –

，所以你需要用它應用數組排序？ –

是的，同樣的數組我要去迭代 –

你可以讓一個數組，然後再排序它Array#sort()與想要的那種層次的回調。

var object = { "QVC": { "p1": 0, "p2": 12, "p3": 12, "total": 24, "org": "QVC" }, "TURNER & TOWNSEND": { "p1": 12, "p2": 12, "p3": 0, "total": 24, "org": "TURNER & TOWNSEND" }, "EDF ENERGY": { "p1": 12, "p2": 0, "p3": 12, "total": 24, "org": "EDF ENERGY" }, "TOWERS WATSON": { "p1": 6, "p2": 0, "p3": 6, "total": 12, "org": "TOWERS WATSON" }, "VODAFONE UK LTD": { "p1": 0, "p2": 1, "p3": 0, "total": 1, "org": "VODAFONE UK LTD" }, "DENPLAN LTD": { "p1": 1, "p2": 0, "p3": 0, "total": 1, "org": "DENPLAN LTD" } }, 
 
    array = Object.keys(object).map(function (k) { return object[k]; }); 
 

 
array.sort(function (a, b) { 
 
    return a.total - b.total || a.p1 - b.p1 || a.p2 - b.p2 || a.p3 - b.p3; 
 
}); 
 

 
console.log(array);

來源

2016-06-01 10:52:19

這和我想要的完全一樣 –

無法排序對象，但你可以用Object.keys()創建對象鍵的排列和排序它

var obj = {"QVC":{"p1":0,"p2":12,"p3":12,"total":24,"org":"QVC"},"TURNER & TOWNSEND":{"p1":12,"p2":12,"p3":0,"total":24,"org":"TURNER & TOWNSEND"},"EDF ENERGY":{"p1":12,"p2":0,"p3":12,"total":24,"org":"EDF ENERGY"},"TOWERS WATSON":{"p1":6,"p2":0,"p3":6,"total":12,"org":"TOWERS WATSON"},"VODAFONE UK LTD":{"p1":0,"p2":1,"p3":0,"total":1,"org":"VODAFONE UK LTD"},"DENPLAN LTD":{"p1":1,"p2":0,"p3":0,"total":1,"org":"DENPLAN LTD"}} 
 

 
var sort = Object.keys(obj).sort(function(a, b) { 
 
    return obj[b].total - obj[a].total || obj[b].p1 - obj[a].p1 || obj[b].p2 - obj[a].p2 || obj[b].p3 - obj[a].p3; 
 
}) 
 

 
console.log(sort)

然後你就可以使用該鍵的排序數組的排序返回對象值訂購

var obj = {"QVC":{"p1":0,"p2":12,"p3":12,"total":24,"org":"QVC"},"TURNER & TOWNSEND":{"p1":12,"p2":12,"p3":0,"total":24,"org":"TURNER & TOWNSEND"},"EDF ENERGY":{"p1":12,"p2":0,"p3":12,"total":24,"org":"EDF ENERGY"},"TOWERS WATSON":{"p1":6,"p2":0,"p3":6,"total":12,"org":"TOWERS WATSON"},"VODAFONE UK LTD":{"p1":0,"p2":1,"p3":0,"total":1,"org":"VODAFONE UK LTD"},"DENPLAN LTD":{"p1":1,"p2":0,"p3":0,"total":1,"org":"DENPLAN LTD"}} 
 

 
var sort = Object.keys(obj).sort(function(a, b) { 
 
    return obj[b].total - obj[a].total || obj[b].p1 - obj[a].p1 || obj[b].p2 - obj[a].p2 || obj[b].p3 - obj[a].p3; 
 
}) 
 

 
sort.forEach(function(e) {console.log(obj[e]) });

來源

2016-06-01 10:51:44

你可以嘗試http://eloquentjavascript.net/和https://developer.mozilla.org/en-US/docs/Web/JavaScript –

基於多個屬性根據優先級排序javascript對象

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