從XML文件中選擇所有的人在哪裏=「鮑勃」

Question

所以，當我使用PHP與MySQL我只是做：

$result = $mysqli->query("SELECT * FROM table WHERE person='Bob'"); 

我現在使用PHP的XML和我沒有帶一個線索如何做這個。我試過Google搜索，但我不知道這將在XML中被調用。

我的XML是：

<People> 
    <person>Bob</person> 
    <about>Bob is a blob. He is 20 Years old, etc</about> 
</People> 
<People> 
    <person>Jim</person> 
    <about>Jim is 90 Years old, he plays basketball, etc</about> 
</People> 
<People> 
    <person>Steve</person> 
    <about>Steve is a superhero with the ability to fly.</about> 
</People> 

基本上，我想回應某個人的信息。因此，如果吉姆用戶搜索，將呼應：

Name: Jim 
About: Jim is 90 Years old, he plays basketball, etc 

Answer 1

使用XPath。

XML：

<data> 
    <People> 
     <person>Bob</person> 
     <about>Bob is a blob. He is 20 Years old, etc</about> 
    </People> 
    <People> 
     <person>Jim</person> 
     <about>Jim is 90 Years old, he plays basketball, etc</about> 
    </People> 
    <People> 
     <person>Steve</person> 
     <about>Steve is a superhero with the ability to fly.</about> 
    </People> 
</data> 

PHP代碼：

$xml = new SimpleXMLElement($xml_string); 
$result = $xml->xpath('/data/People[person="Jim"]'); 
var_dump($result); 

輸出：

array(1) { 
    [0]=> 
     object(SimpleXMLElement)#2 (2) { 
      ["person"]=> 
       string(3) "Jim" 
      ["about"]=> 
       string(45) "Jim is 90 Years old, he plays basketball, etc" 
     } 
}