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如果用戶輸入特定的輸入,我必須跳出循環。但我無法使用if循環來打破while循環。我也嘗試在while循環中使用相同的條件,但這也不起作用。無法擺脫while循環。
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
String quit;
Scanner c = new Scanner(System.in);
while (true) {
leapOrNot y = new leapOrNot();
System.out.println("press x to stop or any other letter to continue");
quit = c.next();
if (quit == "x" || quit == "X") {
break;
}
}
}
}
class leapOrNot {
final String isLeap = " is a leap year.";
final String notLeap = " is not a leap year.";
int year;
public leapOrNot() {
Scanner a = new Scanner(System.in);
System.out.println("Enter a year after 1581: ");
year = a.nextInt();
/* if (a.hasNextInt() == false) {
System.out.println("Enter a 4 digit integer: ");
year = a.nextInt();
}
couldn't make this condition work either
*/
while (year < 1582) {
System.out.println("The year must be after 1581. Enter a year after 1581: ");
year = a.nextInt();
continue;
}
if (year % 4 == 0) {
if(year % 400 == 0 && year % 100 == 0) {
System.out.println(year + isLeap);
}
if (year % 100 == 0) {
System.out.println(year + notLeap);
}
else {
System.out.println(year + isLeap);
}
}
else {
System.out.println(year + notLeap);
}
}
}
提示:'c.next()toLowerCase()'將有助於降低你的平等 –
不要使用''==或'='比較字符串!改爲使用「equals(...)」或「equalsIgnoreCase(...)」方法。理解'=='檢查兩個*對象引用*是否相同,而不是你感興趣的。另一方面,方法檢查兩個字符串是否具有相同順序的相同字符,這就是這裏很重要。 –