第一次在這裏發佈海報,所以請原諒任何發佈錯誤。也是Android的新手,我有一個問題試圖找出共享首選問題。我聲明我的常數如下SharedPreference ClassCastException問題Android
private static SharedPreferences mSharedPreferences;
static final String TWEET = null;
static final String MEAL_ID = null;
和我的共享偏好如下
mSharedPreferences = getApplicationContext().getSharedPreferences(
"MyPref", 0);
我的簡單測試代碼如下:
String msgTemp = "testing";
long iDTest = 234;
Editor e = mSharedPreferences.edit();
e.putLong(MEAL_ID, iDTest);
e.putString(TWEET, msgTemp);
e.commit();
String tempMsg = mSharedPreferences.getString(TWEET, "");
long tempId = mSharedPreferences.getLong(MEAL_ID, 0);
Toast.makeText(getApplicationContext(),
"Msg: " + tempMsg + " " + "ID: " + tempId, Toast.LENGTH_LONG).show();
返回以下錯誤:
03-25 15:47:41.386: E/AndroidRuntime(28321): java.lang.ClassCastException: java.lang.String cannot be cast to java.lang.Long03-25 15:47:41.386: E/AndroidRuntime(28321): at android.app.SharedPreferencesImpl.getLong(SharedPreferencesImpl.java:228)
howev呃,如果我切換2「把」線路中的代碼是這樣的:
String msgTemp = "testing";
long iDTest = 234;
Editor e = mSharedPreferences.edit();
e.putString(TWEET, msgTemp);
e.putLong(MEAL_ID, iDTest);
e.commit();
String tempMsg = mSharedPreferences.getString(TWEET, "");
long tempId = mSharedPreferences.getLong(MEAL_ID, 0);
Toast.makeText(getApplicationContext(),
"Msg: " + tempMsg + " " + "ID: " + tempId, Toast.LENGTH_LONG).show();
我收到以下錯誤:
03-25 15:50:16.551: E/AndroidRuntime(28838): java.lang.ClassCastException: java.lang.Long cannot be cast to java.lang.String 03-25 15:50:16.551: E/AndroidRuntime(28838): at android.app.SharedPreferencesImpl.getString(SharedPreferencesImpl.java:205)
所以,在我看來,該值是進入喜好以錯誤的順序,但我不知道爲什麼。我試過在輸入新值之前清除這些值,如下所示:
String msgTemp = "testing";
long iDTest = 234;
Editor e = mSharedPreferences.edit();
e.remove(MEAL_ID);
e.remove(TWEET);
e.putLong(MEAL_ID, iDTest);
e.putString(TWEET, msgTemp);
e.commit();
String tempMsg = mSharedPreferences.getString(TWEET, "");
long tempId = mSharedPreferences.getLong(MEAL_ID, 0);
Toast.makeText(getApplicationContext(),
"Msg: " + tempMsg + " " + "ID: " + tempId, Toast.LENGTH_LONG).show();
但是那樣做什麼也沒有。任何人都可以爲我闡明這一點嗎?
你常數MEAL_ID和TWEET沒有價值,所以你要2個不同的值,在SharedPreferences添加到同一個對象, 'null'對象 - 我不知道爲什麼這是可能的,但顯然它是;-) – Darwind 2013-03-25 20:07:48